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My name is Ann [436]
3 years ago
8

Factors of 3xsquared-9x-12

Mathematics
2 answers:
Doss [256]3 years ago
8 0

Answer:

  • 3(x^{2} -3x-4)

Step-by-step explanation:

Hope it helps! :)

blagie [28]3 years ago
4 0

Answer:

3x ^{2}  - 9x - 12 = 3(x - 4)(x + 1)

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Two points located on are J(1,-4) and K(-2,8). What is the slope of ?
vodka [1.7K]

Answer:

-4

Step-by-step explanation:

The slope is usually a function of the differences in y divided by the differences in x, and it can be described in the following equation,

Slope = \frac{y_{1} - y_{2} }{x{1} - x{2}}     (1)

We can select any of the two points to be our first point, let's say, J(1,-4) is point 1, so J (x1,y1). In other words, x_1 = 1 and y_1 = -4 and by the same way, for K(-2,8). Therefore, x_2 = -2 while y_2 = 8. By substituting these values in equation 1, we can deduce the following

slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{8 - (-4)}{-2 - 1} = \frac{8 + 4}{-2 - 1} = \frac{12}{-3} = -4

3 0
2 years ago
What is the range of 5,4,6,3,4?
AlekseyPX

Answer:

Range=2

Step-by-step explanation:

Range=Highest number-Lowest number

          =5-3=2

Hope it Help

Mark Me Brillainest

6 0
3 years ago
All of the following expressions are equivalent except _____.
omeli [17]

Answer:

x - 7

Step-by-step explanation:

7 - 1= 6

1 - 7= -6

-1 + 7= 6

7 + (-1) =6

8 0
3 years ago
2x 26<br> Please I need help I am failing math !!
almond37 [142]

Answer:

2*26=52

Step-by-step explanation: you can just use a calculator to find 2*26 and you will find that the answer to your question is 52.

3 0
4 years ago
Read 2 more answers
Plz answer!! ASAP!!
Wittaler [7]

(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°

(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°

Solution:

(1) In the given image ABC and DBE are vertical angles.

<u>Vertical angle theorem:</u>

If two angles are vertical then they are congruent.

⇒ ∠ABC = ∠DBE

⇒ 3x° + 38° = 5x° + 20°

Arrange like terms one side.

⇒ 38° – 20° = 5x° – 3x°

⇒ 18° = 2x°

⇒ x° = 9°

∠ABC = 3(9°) + 38° = 65°

∠DBE = 5(9°) + 20° = 65°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 65° + ∠CBE = 180°

⇒ ∠CBE = 115°

∠ABD and ∠CBE are vertical angles.

∠ABD = 115°

(2) In the given image ABC and DBE are vertical angles.

⇒ ∠ABC = ∠DBE

⇒ 4x° + 2° = 5x° – 13°

Arrange like terms one side.

⇒ 13° + 2° = 5x° – 4x°

⇒ 15° = x°

∠ABC = (4(15°) + 2°) = 62°

∠DBE = 5(15°) – 13° = 62°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 62° + ∠CBE = 180°

⇒ ∠CBE = 118°

∠ABD and ∠CBE are vertical angles.

∠ABD = 118°

3 0
3 years ago
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