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3 years ago

Solve for x: 2/7(x-2) = 4x

Mathematics

1 answer:

zheka24 [161]3 years ago

8 0

Answer:

2/7(x-2)=4x

(2×x-2×2)/7 = 4x

(2x-4)/7 = 4x

2x-4×(1) = 4x × 7 ( Cross multiply)

2x-4 = 28

2x = 32

2x÷2 = 32÷2

x=16

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Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$

Therefore, we get

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98$

So, the sample standard deviation is 6.98.

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3 years ago

Can these side lengths make a triangle 12,13,7 ? yes no are in possible

notsponge [240]

Answer: I think it’s yes?

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3 years ago

What is the value of the expression

Inga [223]

Answer:

The answer is ten or Letter C

Step-by-step explanation:

You plug in the values of w and x so you get 3(1/4*8)+4. Multiply whats in the parthensis then distribute the 3 into 2 and get 6. So 6+4=10. Thats the answer for this expression. I hope this helps!

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3 years ago

Read 2 more answers

Scientific notation 9.78 × 10^5 - 732,000 It has to be either 2.46 × 10^5 or 2.46 × 10^3

Morgarella [4.7K]

Answer:

$2.46\times 10^5$