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snow_lady [41]
3 years ago
7

A room has 332 square feet that need painting. If a one-gallon can of paint covers 250 square feet, how many cans are needed to

paint the room?
Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

2 cans of paint are needed to paint 332 square feet.

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Victoria has $2.90 in quarters, dimes and nickels. The numbers of nickels is one more than six times the number of quarters, and
maria [59]

Answer:

Step-by-step explanation:

She has 290 cents.

Nickels: 6x+1

Quarters: x

Dimes: 4x

Now that we've converted it algebraically, we can add them

6x+1 + x + 4x = 11x+1 = 290

11x = 289

x = 289/11

let me know if incorrect, i will fix

8 0
3 years ago
A plant grows at a constant rate of __ cm per day.
devlian [24]

Plant grows at 3CM per day

equation: y= 3x

21 is y so 21= 3x. divide by 3 so it's been 7 days

3 0
3 years ago
what’s the slope and y intercept of the loire that is perpendicular to y=-2x-5 and passes through the point (-3,-6)
Doss [256]

Answer:

slope: ½

y-intercept: -4½

Step-by-step explanation:

Slope: negative reciprocal of -2

-1/-2 = 1/2

y = ½x + c

-6 = ½(-3) + c

-6 = -3/2 + c

c = -6 + 3/2

c = -9/2 = -4½

8 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
3 years ago
A quadratic function is defined by g(x) = (x + 4)2 +7.
Travka [436]

Step-by-step explanation:

The vertex is the point (-4, 7).

4 0
3 years ago
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