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amid [387]
3 years ago
10

You're flying in a twin-engine turboprop aircraft, with its two propellers turning at 977 and 998 rpm , respectively.

Physics
1 answer:
Elina [12.6K]3 years ago
6 0

Answer:

Explanation:

998 - 977 = 21 peaks /minute or about every 2.86 seconds

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1. Starting today. I will now change my behavior/s like ______________ because _________________
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be mature, it's the only way to be called independent, I will help my parents with doing chores, you will meet new friends

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it's just my own understanding

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What is the uses of echoes​
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6 0
3 years ago
An upward electric force of 10 N is exerted on a 3 C charge. Find the magnitude and direction of the electric field at the posit
Tresset [83]

The magnitude and direction of the electric field at the position of this charge.3.33 N/C upward

An electric field is the electric force per unit of charge. It is assumed that the field's direction corresponds to the direction in which a positive test charge would experience force. The electric field is directed radially inward toward a negative point charge and radially outward from a positive charge.

Value of force F given  = 10N

value of charge Q = 3 C

We know that E = F/Q

E = 10/3

= 3.33N

where charge is scalar quantity so the direction of force is the direction of electric field

Hence the magnitude and direction of the electric field at the position of this charge.3.33 N/C upward

Learn more about Electric field here

brainly.com/question/25751825

#SPJ4

8 0
2 years ago
A 8.3-g wad of sticky clay is hurled horizontally at a 82-g wooden block initially at rest on a horizontal surface. The clay sti
Bingel [31]

Answer:

The speed of the clay before the impact was 106.35 m/s.

Explanation:

the only force doing work on the system is the frictional force, f, the work done by f is given by:

Wf = ΔK = Kf - Ki

The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:

         f×Δx = Ki

m×g×Δx×μ = 1/2×m×v^2

           v^2 = 2×g×Δx×μ

                  =  2×(9.8)×(7.50)×(0.650)

                  = 95.55

               v = 9.78 m/s

This is the veloty of clay and block after the clay hit the block.

if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:

m×v1 +M×V = v(m + M)

         m×v1 = v(m + M)

              v1 = v(m + M)/m

              v1 =  (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)

              v1 =  106.35 m/s

Therefore, the speed of the clay before the impact was 106.35 m/s.

3 0
3 years ago
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