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disa [49]
3 years ago
8

The Hawaiian islands formed when molten material erupted from the ocean floor. As the lava flowed out, cooled, and hardened, mas

sive rocks formed. These rocks have a very fine texture and tiny crystals that cannot be seen with the naked eye. These massive rocks formed into the islands that are present today.
What type of igneous rock are the Hawaiian islands?
Physics
2 answers:
murzikaleks [220]3 years ago
5 0

Answer:

Extrusive ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

lara [203]3 years ago
4 0

Answer:

Explanation:

The most common type of igneous rock making up the Hawaiian island chain is Mafic rock. Furthermore, the most common type of Mafic rock is basalt.

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Would anybody be able to help me complete this sentence?<br><br>Thanks ​
romanna [79]

Answer:

x-axis

Explanation:

when it is at rest, horizontal, on a graph it is the x-axis.

Hope this helped!

7 0
3 years ago
A physicist comes across an open container which is filled with two liquids. Since the two liquids have different density, there
Dominik [7]

Answer:

496.57492 kg/m³

Explanation:

P_a = Atmospheric pressure = 101300 Pa

\rho_w = Density of water = 1000 kg/m^3

h_w = Height of water = 21.8 cm

h_f = Height of fluid = 30 cm

g = Acceleration due to gravity = 9.81 m/s²

\rho_f = Density of the unknown fluid

Absolute pressure at the bottom

P_{abs}=P_a+\rho_wgh_w+\rho_fgh_f\\\Rightarrow \rho_f=\frac{P_{abs}-P_a-\rho_wgh_w}{gh_f}\\\Rightarrow \rho_f=\frac{104900-101300-1000\times 9.81\times 0.218}{9.81\times 0.3}\\\Rightarrow \rho_f=496.57492\ kg/m^3

The density of the unknown fluid is 496.57492 kg/m³

6 0
3 years ago
A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19°C. When the balloon is released, it rises to an alti
inn [45]

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm  Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

3 0
3 years ago
A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
4 years ago
Can someone check my answers please??
loris [4]
I checked them they are good.
3 0
4 years ago
Read 2 more answers
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