Answer:
Explanation:
Work done on the lever ( input energy ) = force applied x input distance
= 24 N x 2m = 48 J
Work done by the lever ( output energy ) = load x output distance
= 72 N x 0.5m = 36 J
efficiency = output energy / input energy
= 36 J / 48 J
= 3 / 4 = .75
In percentage terms efficiency = 75 % .
Left:
2*g-TL=2*aL
aL=α*0.231
therefore
TL=2*(g-α*0.231)
Right:
TR-1.4*g=4*aR
aR=α*0.272
therefore
TR=1.4*(g+α*0.272)
Wheels:
TL*0.231-TR*0.272=
(2*0.231^2+2.3*0.272^2)*α
combine and solve for α
KE= (1/2) mv²
So, the variables we need to include in our question would be a varable for a mass(m) of an object at some velocity(v).
My Answer:
(This is just an example question, yours can be different)
What is the Kinetic Energy experienced by an bouncy ball rolling at 7m/s (that's your velocity) across a frictionless surface that has a mass(m) of 10 grams?
A table would be the most appropriate because that way you can compare the data.
