x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False
Answer:
(x/4) +1 OR (4/x)+1
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given:</u>
- I = 5% = 0.05
- t = 2 years
- Let the sum is x.
<u>Simple interest:</u>
<u>Compound interest:</u>
- CI = x*(1 + 0.05)² - x = 1.1025x - x = 0.1025x
<u>The difference is 230:</u>
- 0.1025x - 0.1x = 230
- 0.0025x = 230
- x = 230/0.0025
- x = 92000
2 4/5 I believe is the least value.
Answer:
below in bold
Step-by-step explanation:
f(x) = 2x - 7 - 3
~Combine like terms
f(x) = 2x - 10
When x = 2...
f(x) = 2(2) - 10
f(x) = 4 - 10
f(x) = -6
When x = 3...
f(x) = 2(3) - 10
f(x) = 6 - 10
f(x) = -4
When x = 4...
f(x) = 2(4) - 10
f(x) = 8 - 10
f(x) = -2
Best of Luck!
