I believe your last coordinate would be (6,3)
We can automatically rule out both Right and Equilateral Triangles, this is because there is no 90 degree angle (Needed for a right triangle) and all three angles are not equal (needed for an equilateral triangle).
Looking a little deeper, we know that an isosceles triangle has two congruent (or same) angles. Meaning we can rule this one out as well.
This leaves option A) Scalene Triangle
And to check, we think about a scalene triangle, and we know it's a triangle that has 3 unequal sides, meaning that this could qualify!
The plane will end up flying 5.02°.
The plan's speed relative to the ground will be 645.91 km/hr.
Solution:
Use the cosine formula,

Substitute the given values in the formula,




Taking square root on both sides, we get
R = 645.91 km/hr
This is the grouped speed of the aircraft.
To find θ use sine rule.


Do cross multiplication, we get


sin θ = 0.0875
θ = 5.02°
This is known as the drift angle and is the correction the pilot should apply to remain on course.
The heading is the direction the aircraft's nose is pointing which is
The track is the actual direction over the ground which is θ = 5.02°
An alternative method to this would be to separate each vector into vertical and horizontal components and add.
The resultant can be found using Pythagoras.
Answer:
<h2>9p</h2>
Step-by-step explanation:
9p - 8 + 8
9p - 0
9p
-8 + 8 cancel out.
9p is a variable, and its own term with no like terms. so you leave it alone.
That gives you 9p
Hope that helps!