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Juli2301 [7.4K]
3 years ago
14

Use the graph to answer the question.

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

The interval at which a function increases, is the interval where the output values of the function increase with the input value

<em>The intervals at which the function of the attached graph increases are: </em>(-\infty, -2)\ u\ (2,\infty)<em />

The graph is not given; so, I will explain this question with the attached graph

From the attached graph, we have the following observations:

  • <em>As x increases from </em>-\infty<em> to -2, the value of function increases from 0 to 16.</em>
  • <em>As x increases from 2 to </em>\infty<em>, the value of function increases from -16 to 0.</em>

<em />

So, the intervals at which the function increases are: (-\infty, -2)\ u\ (2,\infty)

Read move about function intervals at:

brainly.com/question/11006056

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Answer:

The answer is Option B

Step-by-step explanation:

<u>Step 1:  Find the points</u>

The leftmost point is:  <em>(-3, -1)</em>

The next point is:  <em>(-2, 2)</em>

The next point is:  <em>(1, 0)</em>

The next point is:  <em>(3, 1)</em>

The rightmost point is: <em> (4, -2)</em>

<em />

Answer:  The answer is Option B

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Need help with these math questions
PSYCHO15rus [73]

\sqrt{16-x}        x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

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2.82842

2.83 You answer is the 4th option


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Plug in 9 for "x" in the equation

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Answer:

(3,22.50)

(6, 33)

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10.5/3

<u>Rate = 3.5</u>

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