Step-by-step explanation:
"Solutions to the equation" just means that they are points on the line. To find out if these two points land on this line, plug each one in, like this:
1.5 = (1/4)(1) + (5/4)
1.5 = (1/4) + (5/4)
1.5 = (6/4)
1.5 = 1.5
Since the expression is true, this point is on the line.
Do the same process for the second point (remember a point is formatted (x,y)) and see if it is also a point on the line.
To find the x-intercept, simply plug in 0 for y and see what you get. It should look like (x,0).
The residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.
<h3>What is residual value?</h3>
The residual value is the estimated value which is calculated for the end of the lease terms for a fixed asset.
Points and their residual values are shown in the table. A 3-column table with 5 rows.
- x 1, 2, 3, 4, 5.
- y 2, 3.5, 5, 6.1, 8.
- Residual Value -0.4, 0.7, -0.2, -0.6 0
The simple regression line can be represented as,
Here α is the constant, β is the slope and <em>e </em>is the residue.
The point which is farthest from the best fit of the line is 3.5. At y=3.5, the value of residue is 0.7.
Thus, the residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.
Learn more about the residual value here;
brainly.com/question/1168961
<span>Answer is: 414 pounds of red fescue and 138 pounds of chewings fescue is needed to produce 552 pounds of mixture.</span>
<span>Explanation:
x - how much of red fescue is needed for one pound of mixture
y - how much of chewings fescue is needed for one pound of mixture</span>x*12+ y*16 = 15<span>x + y = 1
so, x=1-y
putting it into first line:</span><span>(1-y)*12 + y*16 = 15
12 - 12*y + 16*y = 15
4*y = 3
y=3/4
so, x= 1-3/4; x=1/4</span>So to produce 552 pounds of mixture we need..<span>To produce 1 pound of mixture we need: 3/4 pound of red fescue and 1/4 pound of chewing fescue so to produce 552 pounds of miture we need:
552*3/4 - red fescue, which is 414 pounds needed
and
552/4 - chewings fescue, which is 138 pounds needed</span>
Answer: the system has no solution.
Step-by-step explanation:
\displaystyle\\
\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\
Multiply\ both\ sides\ of\ the\ equation\ (2)\ by\ y\ (y\neq 0):\\
x^2y+4y^2+16y=0\\
We\ substitute\ equation\ (1)\ into\ equation\ (2):\\
16+4y^2+16y=0\\
4y^2+16y+16=0\\
4*(y^2+4y+4)=0\\
4*(y^2+2*y*2+2^2)=0\\
4*(y+2)^2=0\\
Divide\ both\ sides\ of\ the \ equation\ by\ 4:\\
(y+2)^2=0\\
(y+2)*(y+2)=0\\
So,\ y+2=0\\
y=-2.\\