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Aleonysh [2.5K]
2 years ago
5

Please help me quick!!

Mathematics
1 answer:
Aneli [31]2 years ago
4 0

Answer:

umm sorry i can't I'm still finding hacker so please like and star please

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when sunayana purcased a video-game she paid Rs 162.50 as VAT at the rate of 13%. find its cost without levying VAT. Rs 1250 is
horsena [70]

Answer: 1250

Step-by-step explanation:

Let x be the cost before vat

13/100x = 162.50

x = 162.50 x 100/13

x = 162.50 / 2.13

x = 1250

3 0
3 years ago
Twelve decreased by twice a number is -8. Find the number
drek231 [11]
<h2>Solution :- </h2>

Let the number be "x" , then according to the question :

• 2x - 12 = -8

Further solving

→ 2x = -8 + 12

→ 2x = 4 .

→ x = 2

8 0
2 years ago
Read 2 more answers
Jana baked some muffins. After she served 13 of them to her friends for brunch, she had 17 left. How many muffins did she bake?
aleksley [76]

Answer:

30

Step-by-step explanation:

Add 13 served to 17 left over to get how many muffins she originally baked.

6 0
1 year ago
Read 2 more answers
How many solutions does the equation sin(4x)= 3/4?
MAVERICK [17]
sin(4x)=  \dfrac{3}{4} 

4x=sin^-^1( \dfrac{3}{4}), \pi -sin^-^1( \dfrac{3}{4}) 

<span>Since sin is a periodic function, add the periodicity. 
</span>
4x=2\pi n+sin^-^1 ( \dfrac{3}{4} ) ,nEZ &#10;&#10; 

4x=2\pi n-sin^-^1 ( \dfrac{3}{4} ) ,nEZ 

x= \dfrac{2\pi n+sin^-^1 ( \dfrac{3}{4} ) }{4},  nEZ 

x= \dfrac{2\pi n+ \pi -sin^-^1 ( \dfrac{3}{4} ) }{4}, nEZ
8 0
3 years ago
A survey of 542 consumers reveals that 301 favor the new design for a product. Construct a 90% confidence interval for the true
kodGreya [7K]

Answer:

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 542, \pi = \frac{301}{542} = 0.555

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 - 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.52

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 + 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.59

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

5 0
3 years ago
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