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3 years ago

Please I need help in this

Mathematics

2 answers:

marishachu [46]3 years ago

8 0

It is C well if you see the line going horizontal that’s is the x-axis and the y-axis is going vertical and the -3 is the x and the -6 is the y so you look for the -3 in the left bottom side where it is all negative and and when you find it you look for the -6 in the y axis line where you move down. These are examples but this is where you can find it if it has a positive or negative or both

belka [17]3 years ago

3 0

Answer:

Point C

Step-by-step explanation:

negative means go left on the x axis and negative on the y axis means go down. Sorry if this explanation doesn't help much.

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Ty very much! Please help? :))

wlad13 [49]

Answer:

Exact Form: 

$\frac{8}{3}$

Decimal Form:

$2.6$

Mixed Number Form:

$2\frac{2}{3}$

Hope this helps :)

-ilovejiminssi♡

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3 years ago

Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4

Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

$p(x)= -x+4x^2+Cx^3-8x^4 \\ \\ \because \: given \: polynmial \: has \: zero \: at \: \\x = \frac{1}{4} \\ \\ \implies \: p\bigg(\frac{1}{4} \bigg) = 0...(1) \\ \\ plug \: x = \frac{1}{4} \: in \: p(x) \: we \: find \\ \\ p \bigg(\frac{1}{4} \bigg) = - \frac{1}{4} + 4 {\bigg(\frac{1}{4} \bigg)}^{2} + c {\bigg(\frac{1}{4} \bigg)}^{3} - 8 {\bigg(\frac{1}{4} \bigg)}^{4} \\ \\ 0 = - \frac{1}{4} + \cancel 4 \times {\frac{1}{\cancel{16} } } + c {\bigg(\frac{1}{64} \bigg)} - \cancel 8 \times \frac{1}{\cancel{256} } \\ \\0 =\cancel{ - \frac{1}{4}} + \cancel {{\frac{1}{4} }} + c {\bigg(\frac{1}{64} \bigg)} - \times \frac{1}{32} \\ \\0 = c {\bigg(\frac{1}{64} \bigg)} - \frac{1}{32} \\ \\c {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32} \\ \\ c = \frac{1}{32} \times 64 \\ \\ c = 2$

5 0

3 years ago

The function y= 19,800/x is a rational function. Use this function to answer each question. What are the asymptotes of the funct

Ilya [14]

Answer:

Step-by-step explanation:

Given the function y = 19800/x

Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

x = 0, y = 0

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yawa3891 [41]

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