For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Answer: slope is -3 and y-intercept is -2
Step-by-step explanation:
when x= 0, y=-2
when x=1, y=-5
i believe you have just to change the value of the letter x in the equation to find the value of y