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Helen [10]
3 years ago
5

Please I need help in this

Mathematics
2 answers:
marishachu [46]3 years ago
8 0
It is C well if you see the line going horizontal that’s is the x-axis and the y-axis is going vertical and the -3 is the x and the -6 is the y so you look for the -3 in the left bottom side where it is all negative and and when you find it you look for the -6 in the y axis line where you move down. These are examples but this is where you can find it if it has a positive or negative or both

belka [17]3 years ago
3 0

Answer:

Point C

Step-by-step explanation:

negative means go left on the x axis and negative on the y axis means go down. Sorry if this explanation doesn't help much.

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I would like to know the process for dis ive been struggling on them. i tried to ask the teacher but they made it more confusing
Dafna11 [192]

Answer:

31.177 m

Step-by-step explanation:

So the formula of a hexagon is  Area = (3√3 s^2)/ 2

s = side in this problem.  A hexagon is made up of 6 equilateral triangles, so the distance from the center is equal to each of the sides.

For this problem, plug and chug.  Plug your knowns into equation and you will find the answer.

s^2 = (2√3)^2 = 12

Area = (3√3 x 12)/2 = 31.1769 m

I am not sure how many decimals you are supposed to round, probably 3 so in that case 31.177 m

8 0
3 years ago
I need this fast guys. This is due tomorrow help a fellow comrade out
gavmur [86]
So whats the answer. please help me I got a test of this
3 0
3 years ago
Find the slope of the line that goes through (-4,2) and (3,-5)
DerKrebs [107]

Answer:

-1

Step-by-step explanation:

m = -7 / 7 = -1 / 1 = -1

5 0
3 years ago
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A homeowner has two different sets of triangular tiles, green tiles and blue tiles. Which of these would prove that the green an
ICE Princess25 [194]
I need a picture to answer the question sorry
8 0
3 years ago
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What is the equation in point-slope form of a line that passes through the points (−4, −1) and (5, 7) ?
Sergio039 [100]

The point-slope form:

y-y_1=m(x-x_1)

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-4, -1) and (5, 7). Substitute:

m=\dfrac{7-(-1)}{5-(-4)}=\dfrac{7+1}{5+4}=\dfrac{8}{9}\\\\\boxed{y-7=\dfrac{8}{9}(x-5)}


6 0
3 years ago
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