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3 years ago

Plz help me in this homework

Mathematics

1 answer:

Nady [450]3 years ago

4 0

Step-by-step explanation:

86 = 1,2,43,86

7 = 1,7

12 = 1,2,3,4,6,12

77 = 1,7,11,77

38 = 1,2,19,38

52 = 1,2,4,13,26,52

9 = 1,3,9

73 = 1,73

98 = 1,2,7,14,49,98

24 = 1,2,3,4,6,8,12,24

6 = 1,2,3,6

80 = 1,2,4,5,8,10,16,20,40,80

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Where do (3/2,-7) and (-4,5) intercept

Vinil7 [7]

Answer:

The intercept of the given points is - $\frac{41}{11}$

Step-by-step explanation:

Given points as :

( $x_1$ , $y_1$ ) = ( $\frac{3}{2}$ , - 7 )

( $x_2$ , $y_2$ ) = ( - 4 , 5 )

Now, slope of line using given points can be written as :

Slope = m = $\dfrac{y_2 - y_1}{x_2 - x_1}$

or. m = $\dfrac{5 - ( - 7 )}{( - 4 ) - [tex]\frac{3}{2}$ }[/tex]

or, m = $\dfrac{12}{( - 4 ) - [tex]\frac{3}{2}$ }[/tex]

or, m = $\frac{12}{\frac{- 8 - 3}{2}}$

Or, m = $\frac{12}{\frac{- 11}{2}}$

∴ m = $\frac{-24}{11}$

So, The slope of the line using points = m = $\frac{-24}{11}$

now, equation of line in slope intercept form can be written as

y - $y_2$ = m × ( x - $x_2$ )

or, y - 5 = $\frac{-24}{11}$ × ( x - ( - 4 ) )

or, y - 5 = $\frac{-24}{11}$ × ( x + 4 )

Or, 11 × ( y - 5 ) = - 24 × ( x + 4 )

Or, 11 y - 55 = - 24 x - 96

Or, 11 y = - 24 x - 96 + 55

Or, 11 y = - 24 x - 41

∴ y = $\frac{-24}{11}$ x - $\frac{41}{11}$

Now, comparing with slope intercept equation

I.e y = m x + c , where c is the intercept

So, The intercept of points is - $\frac{41}{11}$

Hence The intercept of the given points is - $\frac{41}{11}$ Answer

3 0

3 years ago

1 7/11 divided 2 1/2 <br> Show work if you can :)

Dmitry_Shevchenko [17]

You can say 1 and 7/11 is 18/11 and 2 and 1/2 is 5/2 so :
18/11 ÷ 5/2 so 18/11 * 2/5 = 36/55 = 0.654 :)))
i hope this is helpful
have a nice day

6 0

4 years ago

Read 2 more answers

Write a quadratic equation in standard form that has a vertex of (-2, 6) and passes through (-4, -2).

Marizza181 [45]

Answer:

The equation of the quadratic in standard form is:

$y=-2x^2-8x-2$

Step-by-step explanation:

Since they give us the information about where the vertex of the parabola is located, and one extra points where it passes through, we can use the general form of a quadratic in vertex form:

$y-y_v=a\,(x-x_v)^2$

where $(x_v,y_v)$ is the location of the vertex (in our case the point (-2,6).

Therefore the equation above becomes:

$y-y_v=a\,(x-x_v)^2\\y-6=a\,(x-(-2))^2\\y-6=a\,(x+2)^2$

Now,we can use the fact that the point (-4,-2) is also a point of the graph, to find the value of the parameter $"a"$ :

$y-6=a\,(x+2)^2\\-2-6=a\,(-4+2)^2\\-8=a\,(-2)^2\\-8=a\,*4\\a=-2$

Then, the equation of the quadratic with such characteristics becomes:

$y-6=-2\,(x+2)^2\\y-6=-2x^2-8x-8\\y=-2x^2-8x-2$

which is the equation of the quadratic in standard form.

7 0

3 years ago

Last month, customers at a gift shop bought 40 birthday cards,

Iteru [2.4K]

Answer:

32 People

Step-by-step explanation:

I put 40 (Number of birthday cards bought previously) over 125 (Number of expected costumers) and multiplied it by 100 (Total number of card bought previously) to get my answer. Hopefully that helps :)

7 0

3 years ago

What is—<br> 2.5 • 10^-6

dexar [7]

Answer:

0.0000025

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Plz help me in this homework​

Plz help me in this homework