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3 years ago

9

three students make the following claims about determining the average speed and average velocity of the object over the entire

time interval depicted in the graph below … which claim is correct?

1 answer:

Mashcka [7]3 years ago

5 0

Answer:

D. none of them po

Explanation:

pl give me points 73

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Ramu,the gardener,is trying to pull out weeds. however,he has to apply great force.why do you think he has to apply to much forc

jasenka [17]

Answer:

Roots are basically hooked into the ground?

Explanation:

Maybe you could comment here the choices if it's multiple choice.

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2 years ago

A chemical bond results from the mutual attraction of the nuclei for

GenaCL600 [577]

A chemical bond results from the mutual attraction of the nuclei for atoms and electrons.

<u>Explanation:</u>

Each atom tends to have an energy between the nuclei and electrons to keep it stable. So, there will be mutual attraction of the nuclei of atom and of electrons in the innermost shell to the outermost shell. And, this kind of mutual attraction can also be termed as chemical bond or binding energy.

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3 years ago

Deduced hydrochloric acid is a strong acid

Zina [86]

Answer:

for real? i never knew that!:)

Explanation:

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3 years ago

A hunter stood at about 60 m away from a tree. He used the bow to release the arrow in order to shoot a coconut held by a monkey

Sergeeva-Olga [200]

Answer:

$v = u + at (upward)\\ 0 = 45 \sin(20) - 9.81t \\ t = 1.56s$

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3 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

Flura [38]

Answer:

The mass of the wheel is 2159.045 kg

Explanation:

Given:

Radius $r = 0.330$

m

Force $F = 290$ N

Angular acceleration $\alpha = 0.814 \frac{rad}{s^{2} }$

From the formula of torque,

Γ $= I\alpha$ (1)

Γ $= rF$ (2)

$rF = I \alpha$

Find momentum of inertia $I$ from above equation,

$I = \frac{rF}{\alpha }$

$I = \frac{0.330 \times 290}{0.814}$

$I = 117.56$ $Kg. m^{2}$

Find the momentum inertia of disk,

$I = \frac{1}{2} Mr^{2}$

$M = \frac{2I}{r^{2} }$

$M = \frac{2 \times 117.56}{(0.330)^{2} }$

$M = 2159.045$ Kg

Therefore, the mass of the wheel is 2159.045 kg

8 0

3 years ago