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blondinia [14]
3 years ago
9

In straight line motion, if the velocity of an object is changing at a constant rate, then its position is _________ and its acc

eleration is___________: O changing: zero O changing; changing O constant and non-zero; constant and non-zero O None of the above
Physics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

None of the above

It should be position is changing and acceleration is constant.

Explanation:

Since the velocity is changing, this means the object is moving, so the <u>position must also be changing</u>.

Acceleration is the change in velocity in time, if this change of velocity happens at a constant rate, the <u>acceleration must be constant</u> too.

So, for example, if the velocity were to stay the same (not changing), acceleration would be zero, because there wouldn't be a change in time on the velocity.

So in this case the answer sould be position is changing and acceleration is constant. But this isn't in the options so the correct answer is "None of the above"

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If you are going 60 mph what is your speed in m per second
LenKa [72]

Answer:

1/60 mps

Explanation:

We would first have to divide 60 by 60 because there is 60mins per hour to get 1mpm. After that we would have to divide 1 by 60 because there are 60 secs in a min. So our final answer after doing 1/60 would be a fraction.

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3 years ago
Which statement best describes the atoms in a solid?
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<span>A solid formed is described when its resistance is tightly secured, and when it refuses to change shapes. It is one of the four fundamental elements. The best answer would be: The atoms are packed together and cannot move around.</span>
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3 years ago
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Where can Microsoft users browse forums by topic, search existing questions and answers, or ask their own questions?
adoni [48]

Group of answer choices.

A. Community and Forum Resources.

B. Get Live Help.

C. Tech Specs.

D. Top Support Issues.

Answer:

A. Community and Forum Resources.

Explanation:

Microsoft is a multinational corporation that designs and develops various types of software applications or programs such as Microsoft operating system (OS), Microsoft Word, Microsoft Excel, Microsoft Access, Microsoft PowerPoint, etc., to avail end users the ability to perform different tasks on their computers.

Whenever these users encounter a problem with any of these software applications or programs, they can easily go to the official forums and communities to get help from professionals and other end users who may have experienced such problems in the past. These community and forums are typically interactive in nature and as such serves its purpose often times.

Hence, Microsoft users can browse forums by topic, search existing questions and answers, or ask their own questions on Community and Forum Resources.

3 0
3 years ago
Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.30 kg and is initially moving to t
snow_lady [41]

Answer:

a) 3.632 m/s

b) 0.462 m/s

Explanation:

Using the law of conservation of momentum:

m_{1} u_{1} + m_{2} u_{2}= m_{1} V_{1} + m_{2} V_{2}..........(1)

m_{1} = 0.30 kg\\u_{1} = 2.4 m/s\\m_{2} = 0.80 kg\\u_{2} = 0 m/s

Substituting the above values into equation (1) and make V2 the subject of the formula:

0.3(2.4) + 0.80(0)= 0.3 V_{1} + 0.8 V_{2}\\

V_{2} = \frac{0.72 - 0.3 V_{1}}{0.8}..................(2)

Using the law of conservation of kinetic energy:

0.5m_{1} u_{1} ^{2} + 1.2 = 0.5m_{1} V_{1} ^{2} + 0.5m_{2} V_{2} ^{2}\\0.5(0.3) (2.4) ^{2} + 1.2 = 0.5(0.3) V_{1} ^{2} + 0.5(0.8)V_{2} ^{2}\\

2.064 = 0.15 V_{1} ^{2} + 0.4V_{2} ^{2}.......(3)

Substitute equation (2) into equation (3)

2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.72 - 0.3V_{1} }{0.8})  ^{2}\\2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.5184 - 0.432V_{1} + 0.09V_{1} ^{2}  }{0.64}) \\1.32096 = 0.096 V_{1} ^{2} + 0.20736 - 0.1728V_{1} + 0.036V_{1} ^{2} \\0.132 V_{1} ^{2} - 0.1728V_{1} - 1.1136 = 0\\V_{1} = 3.632 m/s

Substituting V_{1} into equation(2)

V_{2} = \frac{0.72 - 0.3 *3.632}{0.8}\\V_{2} = \frac{0.72 - 0.3 *(3.632)}{0.8}\\V_{2} = 0.462 m/s

8 0
3 years ago
A film of oil lies on wet pavement. The refractive index of the oil exceeds that of the water. The film has the minimum nonzero
Rainbow [258]

Answer:

Explanation:

For destructive interference , the condition is

2μt = nλ

2μt = n x 678

For constructive interference , the condition is

2μt = (2n+1)λ₁ /2

n x 678 = (2n+1)λ₁ /2

λ₁ = 1356 n / ( 2n + 1 )

λ₁ = 1356  / ( 2 + 1/n )

For longest wavelength , denominator should be smallest or n should be largest . The longest value of n is infinity so

λ₁ = 1356  /  2

= 678 nm .

7 0
3 years ago
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