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3 years ago

Which sphere is NOT a part of the cycling of oxygen through Earths systems ?

1 answer:

5 0

The answer would be Exosphere because, there are 3 main regions that circulate oxygen through the Earths system, which are the Biosphere, Atmosphere, and the Lithosphere.

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9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o

Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

$m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.$

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

$F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).$

Now the force of friction is $F_s=\mu*N,$ where $N$ is the normal force and from the diagram it is $F_y=mg*cos(\theta).$

Thus $F_s=\mu*N=\mu*mg*cos(\theta).$

Therefore,

$F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).$

Substituting the value for $F_H,m,\mu, and \:\theta$ we get:

$F_{tot}= -38.63N.$

Now acceleration is simply

$a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.$

The negative sign indicates that the acceleration is directed up the incline.

Part B:

$d=\frac{1}{2} at^2$

Which can be rearranged to solve for t:

$t=\sqrt{\frac{2d}{a} }$

Substitute the value of $d=0.50m$ and $a=7.7m/s$ and we get:

$t=0.36s.$

which is our answer.

Notice that in using the formula to calculate time we used the positive value of $a$ , because for this formula absolute value is needed.

5 0

3 years ago

The sun is located in

Fiesta28 [93]

Milky Way Galaxy, same one as you.

7 0

2 years ago

Read 2 more answers

PLEASE HELPPP IT DUES IN 30 minutes

Nuetrik [128]

Answer:

140m

70sec I cant show my work but I gave you a push

Explanation:

Brainliest?

6 0

2 years ago

Can you please answer this question.

Montano1993 [528]

Mechanical and chemical. Mechanical breaks down food into smaller pieces. Chemical breaks it down into simpler nutrients that can then be used by cells. Hope this helps!

3 0

2 years ago

Read 2 more answers

You hold glider A of mass 0.125 kg and glider B of mass 0.375 kg at rest on an air track with a compressed spring of negligible

umka2103 [35]

Answer:

0.2 m/s

Explanation:

$m_A$ = Mass of glider A= 0.125 kg

$m_B$ = Mass of glider B = 0.375 kg

$u_A$ = Initial Velocity of glider A = 0 m/s

$u_B$ = Initial Velocity of glider B = 0 m/s

$v_A$ = Final Velocity of glider A = 0.6 m/s

$v_B$ = Final Velocity of glider B

As linear momentum is conserved

$m_{A}u_{A}+m_{B}u_{B}=m_{A}v_{A}+m_{B}v_{B}\\\Rightarrow v_B=\frac{m_{A}u_{A}+m_{B}u_{B}-m_{A}v_{A}}{m_{B}}\\\Rightarrow v_b=\frac{0+0-0.125\times 0.6}{0.375}\\\Rightarrow v_b=-0.2\ m/s$

Magnitude of the glider B at this time is 0.2 m/s

8 0

3 years ago