Answer:
38%
Step-by-step explanation:
Given that X,the hours per week the music student practice follow a normal distribution.
X:N(8,4)
We have to find the percentage of students who practice between 6 and 10 hours.
6<x<10 implies converting to z
We know z = (x-mean)/sigma = (x-8)/4
Hence 6<x<10 is equivalent to (6-8/4)<Z<(10-8/4)
= |z|<0.5
From std normal table we find this area equals = 0.1915+0.1915
=0.3830 = 0.38 (rounded off)
Hence required percentage = 0.38x100 = 38%
Answer is 1.538
Using (x1,y1)(x2,y2)
x1=0
Y1=2
X2=5.2
Y2=10
Answer:
The correct answer is actually around 21%. Are you sure the question wasn't asking what the approximate percent decrease from 85 to 70 was? Because in that case it would be around 17%.
Step-by-step explanation:
Answer:
shown
Step-by-step explanation:
This is the link to the same question i think with a answer, im not good at these types of math but hopefully this helps you guys out! brainly.com/question/13982030
