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2 years ago

Area of 23ft^2 what is the length of a square

Mathematics

2 answers:

Step2247 [10]2 years ago

7 0

Answer:

• Area formula of a square:

${ \tt{area = side \times side}}$

• let s represent dimensions of each side of a square:

${ \tt{23 = s \times s}} \\ \\ { \tt{ {s}^{2} = 23}} \\ \\ { \tt{s = \sqrt{23} }} \\ \\ { \tt{length = 4.8 \: ft}}$

pentagon [3]2 years ago

4 0

Step-by-step explanation:

Area=23ft²

Side=√23ft²

Side=4.8ft

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Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

This has been shown in (c) above

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Step-by-step explanation:

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Step-by-step explanation:

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trasher [3.6K]

Answer:

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Step-by-step explanation:

Let cos a = -⁵/₁₃

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