First we will find the value of x.
To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.
We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.
angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24
Now we can use 24 for x and find the value of angle QRO
angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67
So the answer choice B is the right answer.
Hope this helps :)<span />
Answer:
A
Step-by-step explanation:
Area of a triangle:

In our case:
b=4
h=2
Plug in what we know:

Find the matching solution:
A.) it is 1/2 the area of a rectangle of length 4 units and width 2 units
X B.) it is twice the area of a rectangle of length 4 units and width two units
X C.) it is 1/2 the area of a square of side length 4 units
X D.) it is twice the area of a square of side length 4 units
Answer:
1. 15
2. -23
3. -16
Step-by-step explanation:
1. Find h(-8)
h(t) = 
h(-8) = 
h(-8) = 
2. What is the value of g(-3)
g(x) = 4(x - 5) + 
g(-3) = 4(-3 - 5) 
g(-3) = 4(-8) + 9
g(-3) = -32 + 9
g(-3) = -23
3. Find f(10)
f(x) = 14 - 3x
f(10) = 14 - 3(10)
f(10) = 14 - 30
f(10) = -16