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Masteriza [31]
3 years ago
13

The nth term of a number sequence is n2 - 2

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0

If the <em>n</em>-th term of the sequence is given by <em>n</em> ² - 2, then the 5th term is obtained by simply replacing <em>n</em> with 5 :

5² - 2 = 25 - 2 = 23

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Solve by elimination -6x+6y=6 -6x+3y=-12​
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Answer:

3y=-6 ÷3

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Step-by-step explanation:

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- 2X +3Y=7<br> 5x+8y=-2<br> Solution=(_,_)
Leya [2.2K]

Answer:

The solution is the point (-2,1)

Step-by-step explanation:

we have

-2x+3y=7 ----> equation A

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using a graphing tool

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4 years ago
Which is -3.2 written in the form a/b
Alex

Trust me it is -16/5.

Convert a mixed number by placing the numbers to the right of the decimal over 10. Reduce the fraction. Then convert the mixed number into an improper fraction by multiplying the denominator by the whole number and adding the numerator to get the new numerator. Place this new numerator over the original denominator.

3 0
3 years ago
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Solve the equation for all values of r.<br> (22 – 16) (22 + 49) = 0<br> Please help
wel

<em>Correct expression: </em>(x^2-16)(x^2+49)=0

Answer:

x =  4

x = -4

x = 7i or 7 \sqrt{-1}

x = -7i or (-7) \sqrt{-1}

Step-by-step explanation:

(x^2-16)(x^2+49)=0

We do factorization of x^2 - 16

(x^2-16) = (x+4)(x-4)

(x+4)(x-4)(x^2+49) = 0

We require that any term in the multiplication to be zero to fulfil the requirement

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if x + 4 = 0 then (x+4)(x-4)(x^2+49) = 0

x = -4

if x - 4 = 0 then (x+4)(x-4)(x^2+49) = 0

x = 4

if (x^2+49) = 0 then (x+4)(x-4)(x^2+49) = 0

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we have two roots:

If your course has already worked with complex number and the root of -1 then:

7i and -7i are solution as well

because 7i will be: 7^2 \sqrt{-1} ^2= 49 (-1) = -49\\

and the same reasoning for -7i: (-7)^2 \sqrt{-1} ^2= 49 (-1) = -49

3 0
3 years ago
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