1(1)/(4)-:3= 5/12
5/12 of a cup or 0.146 with a bar on top because the 6 goes on forever.
The answer should be 0.25
Answer:
The probability of missing both two-point conversion attempts is 7.5%
Step-by-step explanation:
We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time
Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;
50%*15% = 0.5 * 0.15 = 7.5%
Therefore, the probability of missing both two-point conversion attempts is 7.5%
(x+y)(x+2y)
Hope this helps! (:
…..I’m so sorry this is hard I wish I could help !!
