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beks73 [17]
3 years ago
13

Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how man

y different combinations of six CD's can he put in the player?
Mathematics
1 answer:
Crank3 years ago
6 0
Adrian can put a total of 1716 combinations in the player. 

The formula to be used is as follows:

total combinations = n!/[r! *(n-r)!]
n = number of disks available  = 13
r = number of disks that be held = 6

= 13! = (13• 12•11•10•9•8•7•6•5•4•3•2•1)/(6! <span>• 7!)
</span>=1716

Thank you for posting your question. Feel free to ask me more.



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What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


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