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3 years ago

Find the value of x A) 3 B) 14 C) 5 D) 2

Mathematics

1 answer:

vesna_86 [32]3 years ago

4 0

Answer:

C) 5

Step-by-step explanation:

The measure of angle TSU is 75°. (180° - 105° because it is a flat angle)

The sum of all the angles of a triangle is 180° as well.

You can write an equation to solve for x.

12x + 9x + 75 = 180

Isolate x.

12x + 9x = 180 - 75

12x + 9x = 105

Add the 12 and the 9.

21x = 105

Find what x is.

x = 105 ÷ 21

x = 5

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Sally has a discount card that reduces the price of her grocery bill in a certain grocery store by 5%. If c represents the cost

amm1812

The original price is c. Then the grocery bill will be: c - 0.05c = 0.95 c. You can also say since the beggining that 5% disscount implies 0.95 factor, which leads to c * 0.95 = 0.95c. Sorry if it’s wrong

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2 years ago

An article in Medicine and Science in Sports and Exercise "Maximal Leg-Strength Training Improves Cycling Economy in Previously

Hatshy [7]

Answer:

The 99% confidence interval for the mean peak power after training is [299.4, 330.6]

$299.4\leq\mu\leq 330.6$

Step-by-step explanation:

We have to construct a 99% confidence interval for the mean.

A sample of n=7 males is taken. We know the sample mean = 315 watts and the sample standard deviation = 16 watts.

For a 99% confidence interval, the value of z is z=2.58.

We can calculate the confidence interval as:

$M-z\sigma/\sqrt{n}\leq\mu\leq M+z\sigma/\sqrt{n}\\\\315-2.58*16/\sqrt{7}\leq\mu\leq 315+2.58*16/\sqrt{7}\\\\315-15.6\leq \mu\leq 315+15.6\\\\299.4\leq\mu\leq 330.6$

The 99% confidence interval for the mean peak power after training is [299.4, 330.6]

5 0

3 years ago

The temperature was 68 F .Later that day the temperature was 82 F .How much does the temperature need to rise or fall to return

ruslelena [56]

The answer is A because 82-14=68.

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3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$