Factoring by grouping usually pairs up the first 2 sets of expressions with the second 2 sets. Ours looks like this, then:

. If we factor out the common x-squared in the first set of parenthesis, along with factoring out the common 5 in the second set, we get this:

. Now the common expression that can be factored out is the (x-9). When we do that, here's what it looks like:

. I'm not sure how far you are going with this. You could set each of those equal to 0 and solve for x in each case. The first one is easy. If x - 9 = 0, then x = 9. The second one involves the imaginary i since x^2 = -5. In that case,

. Hopefully, in what I have given you, you can find what you're looking for.
Answer:
I think its c
Step-by-step explanation:
Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Answer:
4 feet
Step-by-step explanation:
Because if she used 1 feet of ribbon for 3 bows you need to multiply by 4 to 1 foot and you will get 12 bows