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Agata [3.3K]
3 years ago
5

identify the equation of a line in slope-intercept form that is perpendicular to y = -1/3 x + 2 and passes through (2, 10)

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

Step-by-step explanation:

y = -1/3x + 2

m1 = -1/3

Slope of the perpendicular line = -1/m1 = -1 ÷ \frac{-1}{3} = -1*\frac{3}{-1} = 3

Equation of the required line : y = mx +b

y = 3x + b

Plugin x = 2 and y 10 in the above equation

10 = 3*2+ b

10 = 6 +b

10 - 6 = b

b = 4

Equation: y = 3x + 4

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Read 2 more answers
Question 13
natali 33 [55]

Answer:

y - 7 = (x + 5)

Step-by-step explanation:

Point-slope form: y - y1 = m(x - x1)

Slope(m) = 1

Point: (-5, 7) = (x1, y1)

To write the equation in point-slope form, we need to know the slope and one point. Since we were already given the values of the slope and one point, all we have to do is input those values into the equation:

y - y1 = m(x - x1)

y - 7 = 1(x - (-5))

y - 7 = (x + 5)

The equation in point-slope form is: y - 7 = (x + 5)

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