Question

identify the equation of a line in slope-intercept form that is perpendicular to y = -1/3 x + 2 and passes through (2, 10)

Answer 1

Answer:

Step-by-step explanation:

y = -1/3x + 2

m1 = -1/3

Slope of the perpendicular line = -1/m1 = -1 ÷ $\frac{-1}{3}$ = $-1*\frac{3}{-1} = 3$

Equation of the required line : y = mx +b

y = 3x + b

Plugin x = 2 and y 10 in the above equation

10 = 3*2+ b

10 = 6 +b

10 - 6 = b

b = 4

Equation: y = 3x + 4