<span>19 − 6( − k − 2)
Distribute -6:
= 19 + 6k + 12
Combine like terms:
= 6k + 31
Answer: </span>6k + 31
the solutions to the related equation are 0,2,3 .
<u>Step-by-step explanation:</u>
Here we have , function f(x) = x3 – 5x2 + 6x . Graph of this function is given below . We need to find What are the solutions to the related equation . Let's find out:
Solution of graph means the value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !
At x = 0 .
From the graph , at x=0 we have f(x) = 0 i.e.
⇒ 
⇒ 
⇒ 
At x = 2 .
From the graph , at x=2 we have f(x) = 0 i.e.
⇒ 
⇒ 
⇒ 
At x=3 .
From the graph , at x=3 we have f(x) = 0 i.e.
⇒ 
⇒ 
⇒ 
Therefore , the solutions to the related equation are 0,2,3 .
Answer:
904.32 cm^3
Step-by-step explanation:
The formula for the volume of a sphere is V=4/3πr³. Since r is given, we can plug that in for r. I'm assuming that we are using 3.14 for pi, so when we plug in all the values in the equation we get V = 4/3*3.14*6³, which solves out to 904.32.
1. Original equation
2.Distributive property
3. Add 6x to each side
4. Subtract 2 from each side
5. Divide each side by 11
Answer:
Mr. Lim will have $2500
Step-by-step explanation:
Given:
The total amount of money which Mr. Lim, Mr. Tan and Mr. Chan is $8650;
Mr. Lim has $450 more than what Mr. Tan has;
Mr. Chan has double the amount of money than what Mr. Tan has.
Therefore, if we assume that the amount of money Mr. Tan has as x, then...
Total money = Mr. Tan + Mr. Lim + Mr. Chan
therefore,
8650 = x + (x + 450) + 2x
8650 = <u>x + 2x + x</u> + 450
8650 = 4x <u>+ 450</u>
8650 - 450 = 4x
8200 = <u>4</u>x
8200/4 = x
2050 = x
As we assumed earlier, x will be equal to the amount of money Mr. Tan has and the question is asking us how much money Mr. Lim has. To find this out, you have to add $450 to the amount of money Mr. Tan has which is $2050. This is because the question also gives us that Mr. Lim has $450 more that Mr. Tan.
I hope this helped you :)