The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
To learn more on derivatives: brainly.com/question/25324584
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Answer:
y = -5x + 39
Step-by-step explanation:
Plug either ordered pair into the Point-Slope Formula FIRST, <em>y</em><em> </em><em>-</em><em> </em><em>y</em><em>₁</em><em> </em><em>=</em><em> </em><em>m</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>x</em><em>₁</em><em>)</em><em>,</em><em> </em>then convert to Slope-Intercept Form by moving whichever term is nearest to <em>y</em><em>,</em><em> </em>over to the right side of the equivalence symbol to get the above answer.
Answer:28
Step-by-step explanation:
7+7+7+7
Answer:
The answer is 2 561,2785 !!!