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andrew-mc [135]
3 years ago
7

What is the equation of the line, in point-slope form, that passes through the given point and has the given slope? Point (11, 3

) slope: 9
y - 3 = 9(x + 11)

y - 3 = 9(x - 11)

y - 3 = -9(x - 11)

y - 11 = 9(x - 3)


Solve the equation or formula for the indicated variable
s=6r^3t, for t
Mathematics
2 answers:
Zielflug [23.3K]3 years ago
5 0

Answer:

option b

Step-by-step explanation:

GenaCL600 [577]3 years ago
4 0

Answer:

OPTION B

Step-by-step explanation:

When a point on a line and the slope of the line are given the equation of the line is determined using the slope one- point form

                          $ (y - y_1) = m(x - x_1) $

where, m = slope of the line

and $ (x_1,y_1) $ is the point passing through it.

Here $ (x_1,y_1) = (11,3) $ and $ m = 9 $.

Substituting in the formula we have: $ (y - 3) = 9(x - 11) $

This is OPTION B. Hence, the answer.

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Answer:

Equation 1 x=-16

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Step-by-step explanation:

Equation 1

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-2m=16-10

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Step-by-step explanation:

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What is an equation of the line that passes through the points (-4, -5) and<br> (-8, -2)?
nikklg [1K]

Solution:

<u>Step-1: Find the slope of the line.</u>

Formula of slope: y₂ - y₁/x₂ - x₁

  • y₂ - y₁/x₂ - x₁ = Slope
  • => -2 - (-5)/-8 - (-4) = Slope
  • => -2 + 5/-8 + 4 = Slope
  • => 3/-4 = Slope

<u>Step-2: Use the point slope formula to determine the slope.</u>

Point slope form formula: y - y₁ = m(x - x₁)

  • y - y₁ = m(x - x₁) = Equation of line
  • => y - (-5) = -3/4{x - (-4)} = Equation of line
  • => y + 5 = -3/4{x + 4} = Equation of line
  • => y + 5 = -3x/4 - 3 = Equation of line
  • => y = -3x/4 - 8 = Equation of line

The equation of the line is <u>y = -3x/4 - 8.</u>

7 0
2 years ago
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Fill in the missing statement and reason in the proof of the Alternate Exterior Angles Theorem.
ludmilkaskok [199]

Answer:

∠EGB and ∠AGF are congruent;

Transitive Property of Equality

Step-by-step explanation:

The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other

Vertical angles are congruent i.e their measures are equal

Look at the attached graph

Given:

AB // CD

E , G , H , F are col-linear

The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD

∵ AB and EF intersected at point G

∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem

When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent (  vertical angle theorem)

∵ AB // CD and EF is a transversal

∴ m∠AGF = m∠CHF (corresponding angles theorem)

Transitive Property of Equality:  if one angle is equal to two other angles, then the two other angles are equal

 Therefore, If a = b and b = c, then a = c

∵ m∠EGB = m∠AGF

∵ m∠AGF = m∠CHF

∴ m∠EGB = m∠CHF (transitive property theorem)

 ∠EGB and ∠AGF are congruent; Transitive Property of Equality

4 0
3 years ago
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