A cell tower is located 4 miles east and 6 miles north of the center of a small town. The cell tower has a coverage
1 answer:
The distance of the house located 8 miles north on the <em>eastern boundary </em>of the tower is 11.31 miles east of the town.
(a) the diagram of this situation is in the image added.
(b) the distance of the house located 8 miles north on the eastern boundary of the tower is calculated by applying Pythagoras theorem.
![c^2 = a^2 + b^2\\\\c^2 = (8)^2 + (4+ 4)^2 \\\\c^2 = (64) + (64)\\\\c^2 = 128\\\\c = \sqrt{128} \\\\c = 11.31 \ miles \ east \ of \ the \ town](https://tex.z-dn.net/?f=c%5E2%20%3D%20a%5E2%20%2B%20b%5E2%5C%5C%5C%5Cc%5E2%20%3D%20%20%288%29%5E2%20%2B%20%284%2B%204%29%5E2%20%5C%5C%5C%5Cc%5E2%20%3D%20%2864%29%20%2B%20%2864%29%5C%5C%5C%5Cc%5E2%20%3D%20128%5C%5C%5C%5Cc%20%3D%20%5Csqrt%7B128%7D%20%5C%5C%5C%5Cc%20%3D%2011.31%20%5C%20miles%20%5C%20east%20%5C%20of%20%5C%20the%20%5C%20town)
Thus, the distance of the house located 8 miles north on the <em>eastern boundary </em>of the tower is 11.31 miles east of the town.
Learn more here: brainly.com/question/19578095
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