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3 years ago

Shang-Chi is part of Phase 4 of the MCU, which

Mathematics

1 answer:

agasfer [191]3 years ago

6 0

The ratio will be 11:23.

Number of movies in part of Phase 4 of the MCU = 11 movies

Total number of movies in the first three phases = 23.

Therefore, the ratio will be gotten since we know the movies in phase 4 and the total movies so far. This will be:

= 11/23 = 11:23.

In conclusion, the ratio is 11:23.

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“Solve the system using elimination” im not good at math so can someone help me

iris [78.8K]

Answer:

No solutions

Step-by-step explanation:

i did this via substitution so i hope it isn't a problem

3x+y=4

6x+2y=−4

Step: Solve 3x+y=4for y:

3x+y+−3x=4+−3x(Add -3x to both sides)

y=−3x+4

Step: Substitute−3x+4foryin6x+2y=−4:

6x+2y=−4

6x+2(−3x+4)=−4

8=−4(Simplify both sides of the equation)

8+−8=−4+−8(Add -8 to both sides)

0=−12

so there are no solutions

hope this helps!!

8 0

3 years ago

Jason practiced making soccer goals and kept track of the results. He missed 3 goals but made 9 in one practice session. What ca

yawa3891 [41]

He can predict that he will make 18 goals.

7 0

4 years ago

Read 2 more answers

Please explain including w and z in your equation

victus00 [196]

Answer:

w = 9 × z

Hope this helps...

4 0

3 years ago

Please help please help please

yKpoI14uk [10]

Answer:

As per Given Information

→ ∠AOB = 7x-99°

→ ∠COD = 2x + 1°

we have to find the value of x .

∠AOB = ∠COD ( Vertically Opposite Angle)

On putting the value we obtain

➺ 7x-99° = 2x + 1°

➺ 7x -2x = 1° + 99°

➺ 5x = 100°

➺ x = 100°/5

➺ x = 20°

So, the value of x is 20° .

4 0

3 years ago

A company with a fleet of 150 cars found that the emissions systems of only 5 out of the 22 they tested failed to meet pollution

Ugo [173]

Answer: No, the percentage of the fleet out of compliance is not different from their initial thought.

Step-by-step explanation:

Since we have given that

n = 22

x = 5

So, $\hat{p}=\dfrac{x}{n}=\dfrac{5}{22}=0.23$

he company initially believed that 20% of the fleet was out of compliance. Is this strong evidence the percentage of the fleet out of compliance is different from their initial thought.

so, p = 0.2

Hypothesis would be

$H_0:p=\hat{p}\\\\H_a:p\neq \hat{p}$

So, the t test statistic value would be

$t=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\t=\dfrac{0.23-0.20}{\sqrt{\dfrac{0.2\times 0.8}{22}}}\\\\\\t=\dfrac{0.03}{0.085}\\\\t=0.353$

Degree of freedom = df = n-1 = 22-1 =23

So, t{critical value} = 2.080

So, 2.080>0.353

so, we will accept the null hypothesis.

Hence, No, the percentage of the fleet out of compliance is not different from their initial thought.

3 0

3 years ago