Answer:
Adult Tickets: 173
Student Tickets: 43
Explanation:
- To solve this problem, you'll need to set up a system of equations.
- Assume a = # of adult tickets sold
- Assume s = # of student tickets sold
2: a + s = 216; 1: 10.25a+ 8s= 2117.25
2: <<As the total number of tickets sold from both sides is equal to 216>>
1: <<Each adults ticket (a) costs $10.25 and each student ticket (s) costs $8, and the total amount of money earned (2117.25) from sales is the combination of these two))>>
- Note that there are two ways to solve systems of equations (by elimnation and substitution), in this case I'll use elimnation as substitution requires one of the variables in one of the two equations to be isolated.
- In this case, I'll elimnate a.
a + s = 216
10.25a + 8s = 2117.25
- In order to elimnate a, it has to be equal to - 10.25 so that it cancels out + 10.25 (so you have to multiply everything on the first equation by 10.25 ((what you do to one part, you'll do to all the other parts)).
-10.25a -10.25s = -2214
10.25a + 8s = 2117.25
- a cancels, and now you solve accordingly.
-2.25s/-2.25 = -96.75/-2.25
s = 43
- You could solve for a using this same method, but it's easier to use the first formula <<a+s=216>> to find a.
a + 43 = 216
- 43 -43
a = 173
Answer:
He can buy up to 20 tickets (ie 20 tickets or less)
The equation is 10+3.25x+5 = 80
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Explanation:
10 = admission cost
3.25 = cost per ticket
x = number of tickets
3.25x = cost from buying x number of tickets
5 = cost of nachos & coke
10+3.25x+5 = total cost of admission, tickets, and food/drink
10+3.25x+5 = 80 since this is the amount he has in his pocket
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Let's solve for x
10+3.25x+5 = 80
3.25x+15 = 80
3.25x = 80-15 .... subtract 15 from both sides
3.25x = 65
x = 65/3.25 ........ divide both sides by 3.25
x = 20
Billy can buy up to 20 tickets (ie 20 tickets or less).
Answer: 90
Step-by-step explanation: it said i was right
10 x 4 = 40. This should help with the first one.
Answer:
Length = 5 cm, width = 2 cm.
Step-by-step explanation:
If L is the length and W the width we have the equations:
LW = 10 <----- The area.
2L + 2W = 14 <------ The perimeter.
From the first equation L = 10/W so substituting for L in the second equation:
2 * 10/W + 2W = 14
20/W + 2W = 14 Multiplying through by W:
20 + 2W^2 = 14W
2W^2 - 14W + 20 = 0 Dividing by 2:
W^2 - 7W + 10 = 0
(W - 5)(W - 2) = 0
W = 5 or 2.
So W is either 2 or 5 cm.
Substituting W = 2 in LW = 10
L * 2 = 10
L = 5 cm.
The length is longer than the width so the length is 5 cm and the width = 2 cm.
