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xxTIMURxx [149]
2 years ago
11

Please help please help please ​

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
4 0

Answer:

As per Given Information

→ ∠AOB = 7x-99°

→ ∠COD = 2x + 1°

we have to find the value of x .

∠AOB = ∠COD ( Vertically Opposite Angle)

On putting the value we obtain

➺ 7x-99° = 2x + 1°

➺ 7x -2x = 1° + 99°

➺ 5x = 100°

➺ x = 100°/5

➺ x = 20°

So, the value of x is 20° .

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3 years ago
the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

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Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

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4 0
3 years ago
Anyone mind helping me ?
storchak [24]

Answer:

<GOJ

Step-by-step explanation:

O is the center of the circle

So central angle is <GOJ

3 0
3 years ago
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