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3 years ago

100.pts and brainleast

Mathematics

2 answers:

erastova [34]3 years ago

7 0

Answer:

The hypothesis of a conditional statement is the phrase immediately following the word if. The conclusion of a conditional statement is the phrase immediately following the word then. Hypothesis: Two angles are adjacent

Step-by-step explanation:

Alex787 [66]3 years ago

3 0

1. Hypothesis: If you were to walk to the movie theater depending on its distance from where you are traveling or walking from could or would be longer then it would if you biked or drove (using a car) there.

2. If today is not Thrusday, then tommmorw is not Friday.

3. Both are true

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Need help ASAP please

KatRina [158]

Answer: choice D) 5

Step-by-step explanation:

22.5/9=2.5

23.5/2.5=9.4

9.4-4.4=5=x

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3 years ago

Alfonso mails a package that weighs 9 lb. How many Oz is this package

andrew-mc [135]

9 × 16 = 144 the answer is 144

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3 years ago

8y : 10y in its simplest form

Harrizon [31]

4y:5y would be the simplest form

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4 years ago

Read 2 more answers

Prove that if $w,z$ are complex numbers such that $|w|=|z|=1$ and $wz\ne -1$, then $\frac{w+z}{1+wz}$ is a real number.

mr_godi [17]

Answer:

See proof below

Step-by-step explanation:

Let $r=\frac{w+z}{1+wz}$ . If w=-z, then r=0 and r is real. Suppose that w≠-z, that is, r≠0.

Remember this useful identity: if x is a complex number then $x\bar{x}=|x|^2$ where $\bar{x}$ is the conjugate of x.

Now, using the properties of the conjugate (the conjugate of the sum(product) of two numbers is the sum(product) of the conjugates):

$\frac{r}{\bar{r}}=\frac{w+z}{1+wz} \left(\frac{1+\bar{w}\bar{z}}{\bar{w}+\bar{z}}{\right)$

= $\frac{(w+z)(1+\bar{w}\bar{z})}{(1+wz)(\bar{w}+\bar{z})}=\frac{w+z+w\bar{w}\bar{z}+z\bar{z}\bar{w}}{\bar{w}+\bar{z}+\bar{w}wz+\bar{z}zw}=\frac{w+z+w+|w|^2\bar{z}+|z|^2\bar{w}}{\bar{w}+\bar{z}+|w|^2z+|z|^2w}=\frac{w+z+\bar{z}+\bar{w}}{\bar{w}+\bar{z}+z+w}=1$

Thus $\frac{r}{\bar{r}}=1$ . From this, $r=\bar{r}$ . A complex number is real if and only if it is equal to its conjugate, therefore r is real.

3 0

3 years ago

Find all values of k for which the function y=sin(kt) satisfies the differential equation y′′+16y=0. Separate your answers by co

VashaNatasha [74]

Answer: k = 4, k = -4 and k = 0.

Step-by-step explanation:

If we have y = sin(kt)

then:

y' = k*cos(kt)

y'' = -k^2*son(x).

then, if we have the relation:

y'' - y = 0

we can replace it by the things we derivated previously and get:

-k^2*sin(kt) + 16*sin(kt) = 0

we can divide by sin in both sides (for t ≠0 and k ≠0 because we can not divide by zero)

-k^2 + 16 = 0

the solutions are k = 4 and k = -4.

Now, we have another solution, but it is a trivial one that actually does not give any information, but for the diff equation:

-k^2*sin(kt) + 16*sin(kt) = 0

if we take k = 0, we have:

-0 + 0 = 0.

So the solutions are k = 4, k = -4 and k = 0.

4 0

3 years ago