Answer:
Option B
Step-by-step explanation:
From the picture attached,
In ΔABC,
m∠B = m∠C = 75° [Isosceles triangles]
By applying triangle sum theorem,
m∠A + m∠B + mC = 180°
m∠A + 75° + 75° = 180°
m∠A = 180° - 150°
m∠A = 30°
In triangle PQR,
m∠P = m∠Q [Isosceles triangle]
By applying triangle sum theorem,
m∠P + m∠Q + m∠R = 180°
2(m∠P) + 30° = 180°
m∠P = 75°
m∠P = m∠Q = 75°
In ΔABC and ΔRPQ,
m∠B ≅ m∠Q [Given]
m∠C ≅ m∠R [Given]
Therefore, by AA property of similarity of two triangles, both the triangles will be similar.
ΔABC ~ ΔRPQ
Option B will be the answer.
The average price paid by him for the shares after 3 months is ksh. 163.33
<h3>Average</h3>
- Total value of shares bought = ksh.20,000
- Amount of shares bought in the first three months = ksh.120, ksh.160 and ksh.210
Average price paid for the shares after 3 months
= (120 + 160 + 210) / 3
= 490 / 3
= 163.333333333333
Approximately,
ksh. 163.33
Learn more about average:
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The answer would be infinite number of solutions
Answer:
7.5 is the answer you are looking for