Answer/Step-by-step explanation:
Given that ∆GHJ is congruent to ∆XYZ, this:
<G = <X,
<H = <Y = 38°
<J = <Z,
GH = XY = 27 ft
HJ = YZ = 27 ft (two sides of an isosceles ∆ are the same)
GJ = XZ = 18 ft
a. GJ = 18 ft
b. XY = 27 ft
c. ZY = 27 ft
d. m<H = m<Y (corresponding angles)
m<H = 38° (substitution)
e. m<Z = (180 - 38)/2 (base triangles of an isosceles ∆ are equal)
m<Z = 142/2
m<Z = 71°
f. m<J = m<Z (corresponding angles)
m<J = 71° (substitution)
Answer:
Pretty sure you put the wrong picture on this question, but the answer to the one you put is A
Step-by-step explanation:
Answer:
<em>1) y = (x-3)²-12</em>
<em>2) y = 5(x-2)²-9 </em>
Step-by-step explanation:
Given the quadratic expressions
y=x²-6x-3
We are to transform it in the form y=ax²+bx+c
y=(x²-6x)-3
Complete the square of the expression in parenthesis
y = (x²-6x + (6/2)² - (6/2)²)-3
y = (x²-6x+3²-3²)-3
y = (x²-6x+9-9)-3
y = (x²-6x+9)-12
y = (x²-3x-3x+9)-12
y = x(x-3)-3(x-3)-12
y = (x-3)(x-3)-12
y = (x-3)²-12
Hence the transformation is y = (x-3)²-12 where a = 1 and k = -12
For the quadratic equation
y=(5x²-20x)-5
y = 5(x²-4x)- 5
Complete the square of the expression in parenthesis
y = 5(x²-4x+4-4)- 5
y = 5(x²-4x+4)-9
y = 5(x-2)²-9
<em>Hence the transformation is y = 5(x-2)²-9 where a = 5 and k = -9</em>
Jade hiked 1 1/4 miles on the trail. Gretta hiked 1 1/2 times as far on the trail as Jade.
Jade hiked = 
Gretta hiked = ![[tex]1\frac{1}{2} becomes \frac{3}{2}](https://tex.z-dn.net/?f=%5Btex%5D1%5Cfrac%7B1%7D%7B2%7D%20becomes%20%5Cfrac%7B3%7D%7B2%7D)
[/tex] times Jade hiked
So Gretta hiked = 
To multiply two fractions, we multiply numerator with numerator and denominator with denominator
Gretta hiked = 
miles
