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2 years ago

The formula K=C+273.15

Mathematics

2 answers:

tangare [24]2 years ago

5 0

300 Kelvin= 26.85 degrees Celsius

mezya [45]2 years ago

4 0

Answer:

C= K- 273.15

300K= 26.85C

Step-by-step explanation:

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X+46.9=61.5 -46.9 -46.9 ------------------------ x=14.6

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2 years ago

Verify that this trigonometric equation is an identity?

Vlada [557]

$\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}$

$=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2$

8 0

3 years ago

4/5 divided by 3 fraction.......

astra-53 [7]

Answer:

4/15

Step-by-step explanation:

$\frac{\frac{4}{5} }{3}=\frac{4}{5}(\frac{1}{3})=\frac{4}{15}$

5 0

3 years ago

Rewrite the given equation in standard form. f(x) = 5x2

pickupchik [31]

Answer:

a = 5, b = -3 and c =1

Step-by-step explanation:

The standard form of a quadratic equation is expressed as;

f(x) = ax² + bx + c

Given the expression

f(x) = 5x² = 3x - 1

f(x) = 5x² - 3x + 1

Comparing with the general formula;

ax² = 5x²

a = 5

bx = -3x

b = -3

c = 1

Hence a = 5, b = -3 and c =1

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3 years ago

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Rudiy27

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3 years ago