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2 years ago

Solve the absolute value equation |x+4|=|7-x|

Mathematics

1 answer:

Artemon [7]2 years ago

8 0

Answer:

x+7=7-x or

=-(7-x)

x=3/2 is the only solution

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The data represents the body mass index (BMI) values for 20 females. Construct a frequency distribution beginning with a lower

Wittaler [7]

Kindly note that the data supplied is not up to 20. Hence, the answer will be based on the number of data given.

Answer:

Step-by-step explanation:

Given the following data:

BMI of 20 females :

17.7. 33.5. 26.6 24.7

28.8. 23.8. 18.3. 22.1

19.2. 22.6. 22.7. 38.9

27.3. 44.9. 32.2. 23.9

Lower class limit (LCL) = 15.0

Class width = 6.0

Class_interval_____frequency

15.0 - 20.9 _________3

21.0 - 26.9 _________7

27.0 - 32.9 _________3

33.0 - 38.9 _________2

39.0 - 44.9 _________1

4 0

2 years ago

Please try answer the question I put an image in.

liraira [26]

Answer:

An isosceles triangle

Step-by-step explanation:

After solving for all the angles In the Triangle ABC,

Angle B = 80

Angle C = 50

Angle A = 50

An isosceles triangle is a triangle that the base angles are equal.

In the image the triangle has two equal angles.

8 0

2 years ago

Read 2 more answers

You have a bag of bubble gum containing six grape, nine sour apple and five regular flavored pieces. You randomly pick one piece

kipiarov [429]

1/8 I think but I am not 100% sure

7 0

3 years ago

Plsssss this is the last question i need help sos

jenyasd209 [6]

Answer:

ASA

Hope I helped<3

8 0

2 years ago

The average life of individual is 70 years. With a standard deviation of 5.5 years. Assume that the lives of these individuals i

Harlamova29_29 [7]

Answer:

The answer is below

Step-by-step explanation:

Given that:

mean (μ) = 70 years, standard deviation (σ)= 5.5 years.

a) The z score measures how many standard deviation a raw score is above or below the mean. It is given as:

$z=\frac{x-\mu}{\sigma}$ , for a sample size of n, the z score is: $z=\frac{x-\mu}{\sigma/\sqrt{n} }$

Given a sample of 5 turtles, we have to calculate the z score for x = 60 and x = 80.

For x = 60:

$z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{60-70}{5.5/\sqrt{5} } =-4.07$

For x = 80:

$z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{80-70}{5.5/\sqrt{5} } =4.07$

The probability that a mean life of a random sample of 5 such turtles falls between 60 and 80 years = P(60 < x < 80) = P(-4.07 < z < 4.07) = P(z < 4.07) - P(z < -4.07) = 1 - 0 = 1 = 100%

b) The z score that corresponds to top 10% is -1.28.

$z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\-1.28=\frac{x-70}{5.5/\sqrt{5} }\\ x-70=-3\\x=70-3\\x=67\ years$

3 0

2 years ago