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3 years ago

PLEASE HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

zimovet [89]3 years ago

8 0

Answer:

Step-by-step explanation:

This one has a similar concept to the other one solved here. brainly.com/question/24796120

Basically we follow the piece wise function.

Explanation of piece wise function

| -x + 7, x ≤ 1

f(x) = | x³ - 5, -1 < x < 2

| 3 , x ≥ 2

When x in f(x) is less than or equal to 1 than f(x) = -x + 7

When x in f(x) is greater than -1 but less than 2 than f(x) = x³ - 5

When x in f(x) is greater than or equal to 2 than f(x) = 3

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Now lets look back at the question

We want to find f(5,000,000,000,000,000)

Looking at the piece wise function we see that the x in f(x) (5,000,000,000,000,000) follows x ≥ 2 as 5,000,000,000,000,000 is greater than 2. When x is greater than or equal to 2, f(x) = 3, hence f(5,000,000,000,000,000) = 3

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3 years ago

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Let f(x)=x^2+17x+72<br><br><br><br> What are the zeros of the function?

densk [106]

Answer:

The zeros of the given function $f(x)=x^2+17x+72$ is $\left(x+8\right)\left(x+9\right)$ are -8 and -9.

Step-by-step explanation:

Given : Function $f(x)=x^2+17x+72$

We have to find the zeros of the functions.

Consider the given Function $f(x)=x^2+17x+72$

Since, we have to find the zeros of the given functions.

Put f(x) = 0

Thus, $x^2+17x+72=0$

We can solve the given equation using middle term splitting method.

17x can be written as 8x + 9x

$x^2+17x+72=0$ can be written as $x^2+8x+9x+72=0$

Taking x common from first two term and 9 common from last two terms, we have,

$x(x+8)+9(x+8)=0$

Simplify, we have,

$\left(x+8\right)=0$ or $(x+9\right)=0$

x = -8 and x = -9

Apply zero product rule, $a\cdot b= 0 \Rightarrow a=0 \ or \ b=0$

$\left(x+8\right)\left(x+9\right)=0$

Thus, The zero of the given function $f(x)=x^2+17x+72$ is $\left(x+8\right)\left(x+9\right)$ are -8 and -9.

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3 years ago

Find the radius r of the sphere.

AleksandrR [38]

Given:

The volume of the sphere = 12348π in³

To find the radius of the sphere.

Formula

The volume of a sphere of radius r is

$V = \frac{4}{3} \pi r^{3}$

According to the problem,

$\frac{4}{3} \pi r^{3} = 12348\pi$

Eliminating π from both the side.

or, $\frac{4}{3} r^{3}= 12348$

or, $r^{3}=\frac{(12348)(3)}{4}$

or, $r^{3}=9641$

or, $r=\sqrt[3]{9261}$

or, $r=21$

Hence,

The radius of the sphere is 21 inches.

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3 years ago

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