Let s represent the short side of the triangle. The long sides of the triangle are each s+1, and the triangle's perimeter is
... s + (s+1) + (s+1) = 3s+2
The length of one side of the square is s-2, and its perimeter is 4 times that, 4(s-2) = 4s-8. The square and triangle have the same perimeter, so
... 3s+2 = 4s-8
... 10 = s . . . . . . . . add 8-3s to both sides
The length of the shorter side of the triange is 10 units.
The answer would be down 2 units from the y intercept and right 1
4x = 7(x-3)
1. Distribute that multiplicand 7: 4x = 7x - 21
2. Group the x terms together: Subtract 4x from both sides: 0 = 3x - 21
3. Solve for x: Add 21 to both sides: 21 = 3x
4. Divide both sides by 3 to obtain x = 7 (answer)
Answer:
Is just a letter identifying the angle.
Since,Angles of a triangle sum up to 180 ,u add both the given numbers and subtract it from 180
