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Elena L [17]
3 years ago
13

Ms. Molina was driving at a constant speed. She drove 150 miles in 3 hours. At that speed,

Mathematics
1 answer:
N76 [4]3 years ago
8 0

Answer:

450,500,225, and the speed is 50mph

Step-by-step explanation:

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PLEASE HELP ME FAST!!!! ( It's about y-intercept)
Hoochie [10]

Answer:

y = 6x -7

Step-by-step explanation:

1. The equation of any line in slope-intercept form is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.

2. Given that the slope is 6, we plug that value in m, and given that the y-intercept is -7, we plug that value in b:

  • y = mx + b
  • y = 6x - 7
5 0
2 years ago
The product of two consecutive odd integers is 63. If x is the smallest of the integers, write an equation in terms of x that de
kodGreya [7K]

Answer:

x*(x+2)= 63   7 and 9

Step-by-step explanation:

7 0
3 years ago
Que son los numeros?
mylen [45]
Cual numeros? No hay nada
3 0
3 years ago
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" If $6000 is borrowed at 7.5% simple interest for 2 yr, then the amount of interest is "
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u

Step-by-step explanation:

3 0
3 years ago
JL is a common tangent to circles M and K at point J. If angle MLK measures 61ᵒ, what is the length of radius MJ? Round to the n
Sladkaya [172]
3.122

The process to getting this comes in many steps. Firstly, you need to find the angles for JLK and MLJ. To find JLK use the arcsin function using the opposite side and the hypotenuse. 

Arcsin(Opp/Hype) = JLK
Arcsin(.5) = JLK
30 degrees = JLK

This means MLJ = 31 degrees since they add up to 61 degrees. 

Now we need to find the length of LJ, which we can do using the Pythagorean Theorem. 

3^2 + JL^2 = 6^2
9 + JL^2 = 36
JL^2 = 27
JL = \sqrt{27}

Now that we have the angle of MLJ and the length of JL, we can use the tangent function to find MJ.

Tan(angle) = opp/adj
Tan(31) = MJ/\sqrt{27}
\sqrt{27}Tan(31) = MJ
3.122 = MJ
7 0
3 years ago
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