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2 years ago

10

caleb draws 14 dogs on each of 4 posters he draws 18 cats on each of 6 other posters if he draws 5 more dogs on each poster how

many dogs and cats does he draw

1 answer:

kaheart [24]2 years ago

4 0

228 would be ur answer
hope i helped:D

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Use the equation 5x + (–7) = –8x + 6 to determine which statements are true. Check all that apply. The terms 5x and –8x are like

Aleks [24]

5x and -8x are like terms. 6 is not a variable. 5 is the coefficient of the term 5x. X is not the constant.

3 0

2 years ago

Read 2 more answers

list the pair of congruent angles and the extended proportion that relations the corresponding sides for the similar polygons KL

kherson [118]

Answer:

In Polygons KLMNP and HGFDC,

Angles K, L, M, N and P are corresponding to H, G, F, D and C,

And, Sides KL, LM, MN, NP and PK are corresponding to sides HG, GF, FD, DC and CH

If the two figures are similar then their corresponding sides and angles are congruent.

Therefore, If Polygon KLMNP is similar to HGFDC,

Then, ∠ K ≅ ∠ H, ∠ L ≅ ∠ G, ∠ M ≅ ∠ F, ∠ N ≅ ∠ D, ∠ P ≅ ∠ C

And, KL ≅ HG, LM ≅ GF, MN≅FD, NP≅DC, PK≅CH

7 0

2 years ago

In the graph below, line k with equation y = -k makes a 45° angle with the x- and y- axes.

tamaranim1 [39]

Answer:

D. (-5,2)

Step-by-step explanation:

1st reflection = reflection across the line k with the rule:

(x,y)→(-y,-x)

So,

(2,5)→(-5,-2)

2nd reflection = reflection across the x-axis with the rule

(x,y)→(x,-y)

So,

(-5,-2)→(-5,2)

After two consecutive reflections

(2,5)→(5,2)

5 0

2 years ago

Read 2 more answers

After a long study, tree scientists conclude that a eucalyptus tree will grow at the rate of 0.5 6/ (t+4)3 feet per year, where

kipiarov [429]

Answer:

<h2>a) 0.5367feet</h2><h2>b) 0.5223feet</h2><h2>c) 0.7292feet</h2>

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

$\int\limits {0.5 + \frac{6}{(t+4)^{3} } } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} } } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \ where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C$

a) The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from t =1 to t = 2

$\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\ = 0.9167 - 0.5 + 0.12\\= 0.5367feet$

b) The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from t =2 to t = 3

$\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\ = 1.439 - 0.9167\\= 0.5223feet$

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

$\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\ = 0.9167 - 0.1875\\= 0.7292feet$

8 0

2 years ago

To create an entry code, you must first choose 2 letters and then, 3 single-digit numbers. How many different entry codes can

RideAnS [48]

multiply everything together

there are 26 letters and 10 digits

so 26 x 26 x 10 x 10 x 10 = 676,000 combinations

8 0

3 years ago