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dybincka [34]
1 year ago
11

Evaluate the function found in the previous step at X =-3

Mathematics
1 answer:
babunello [35]1 year ago
7 0
x-5y=-4x-2y

In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.

-3-5y=-4(-3)-2y

<em>Multiply -4 and -3 in the function above.</em>

-3-5y=12-2y

<em>Add 3 on both sides of the equation.</em>

-3-5y+3=12-2y+3-5y=15-2y

<em>Add 2y on both sides of the equation.</em>

-5y+2y=15-2y+2y-3y=15

<em>Divide both sides of the equation by -3.</em>

\frac{-3y}{-3}=\frac{15}{-3}y=-5

Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.

Answer:

f(-3) = -5

<em />

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Step-by-step explanation:

Since y is directly proportional to x,

we have y = kx, where k is a real constant.

When x = 15, y = 12.

=> (12) = k(15), k = 0.8.

Therefore we have y = 0.8x.

When x = 2, y = 0.8(2) = 1.6.

The answer is y = 1.6 when x = 2.

7 0
3 years ago
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A company is constructing an​ open-top, square-based, rectangular metal tank that will have a volume of 49 cubic feet. What dime
yawa3891 [41]

Answer:

b = 4.6 ft

h = 2.3 ft

Step-by-step explanation:

The volume of the tank is given by:

b^2*h=49

Where 'b' is the length of the each side of the square base, and 'h' is the height of the tank.

The surface area can be written as:

A=b^2+4bh\\A=b^2+4b*({\frac{49}{b^2}})\\A=b^2+\frac{196}{b}

The value of b for which the derivate of the expression above is zero is the value that yields the minimum surface area:

\frac{dA}{db} =0=2b-\frac{196}{b^2}\\2b^3=196\\b=4.61\ ft

The value of h is then:

h=\frac{49}{4.61^2}\\h=2.31\ ft

Rounded to the nearest tenth, the dimensions are b = 4.6 ft and h = 2.3 ft.

7 0
3 years ago
Isabel is 11 years old. This is 3 years more than twice her brother's age. How old is Isabel's brother? Let b = Isabel's brother
Iteru [2.4K]
The answer would be 4 years old
3 0
3 years ago
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2x + y = 5
Verizon [17]
5x=15
X=3
2(3)+y=5
Y= -1

(3,-1)


6 0
3 years ago
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There are two racks with 40 towels per rack on Tuesday there were €30,000 on Wednesday 50 and on Thursday 25 what fraction on av
ale4655 [162]

Answer:

\frac{7}{16}

Step-by-step explanation:

We have been given that are two racks with 40 towels per rack. On Tuesday there were 30, on Wednesday 50 and on Thursday 25. We are asked to find the fraction on average that is in use for the three days.  

First of all, we will find total number of towel by multiplying 40 by 2.

\text{Total towels}=2\times 40

\text{Total towels}=80

Now we will find average number of towels used on three days.

\text{Average}=\frac{\text{Sum of numbers}}{\text{Total numbers}}

\text{Average}=\frac{30+50+25}{3}

\text{Average}=\frac{105}{3}

\text{Average}=35

Now we need to calculate 35 is what part of 80 to find the fractional use of towels per day as:

\text{Fractional use of towels per day}=\frac{35}{80}

\text{Fractional use of towels per day}=\frac{7}{16}

Therefore, \frac{7}{16} on average is in use for the three days.

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