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iris [78.8K]
3 years ago
7

Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculato

r to find the mean and median. Do the results support or contradict the common belief that the mean body temperature is 98.6​F?
Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

The mean of the dataset is the average, while the median is the middle element.

  • <em>The mean and the median of the given dataset is 98.2</em>
  • <em>The results support the common belief that the mean body temperature is 98.6F</em>

<em />

The mean of the dataset is calculated using:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{99.2+ 99.2 +98.2+............+97.7}{48}

\bar x = \frac{4715}{48}

\bar x = 98.2

The median position is:

Median = \frac{1}{2}(n + 1)

Median = \frac{1}{2}(48 + 1)

Median = \frac{1}{2}(49)

Median = 24.5

This means that the median is the average of the 24th and 25th element

Using the sorted dataset, we have:

Median = \frac{1}{2}(98.2 + 98.2)

Median = 98.2

<em>Because the calculated mean and the common belief (98.6) are close, then we can conclude that the results support the common belief that the mean body temperature is 98.6F</em>

<em />

Read more about mean and median at:

brainly.com/question/17060266

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Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

Z = \frac{X - \mu}{\sigma}

Z = \frac{250 - 150}{75}

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Z = 1.33 has a pvalue of 0.9082.

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If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

Z = \frac{X - \mu}{\sigma}

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X - 150 = 1.645*75

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274 shelters will be needed.

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