All categories

3 years ago

36x^3a+45xa^2=9xa( ) complete the statement.

1 answer:

6 0

9xa is the common factor.

You can complete the statement by dividing the two terms of the expression of the left side by 9xa, and you will get:

36x^3a + 45xa^2 = 9xa ( 4x^2 + 5a)

You might be interested in

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B60" id="TexFormula1" title="\sqrt{60" alt="\sqrt{60" align="absmiddle" class="latex-

Citrus2011 [14]

Answer:

7 & 8

Step-by-step explanation:

$\sqrt{60}$ = 7.7459666924148337703585307995648

Therefore, it lies between the whole numbers 7 & 8.

Hope this helps :)

3 0

2 years ago

Write the equation of the circle with center (-4, 8) and passes through the point (-2, -1)

anzhelika [568]

Answer:

$(x+4)^2+(y-8)^2=85$

Step-by-step explanation:

The standard equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

We know that the center is (-4, 8). So, substitute -4 for h and 8 for k:

$(x-(-4))^2+(y-8)^2=r^2\\$

Simplify:

$(x+4)^2+(y-8)^2=r^2$

Now, we will need to find r.

We know that it passes through the point (-2, -1). So, we can substitute -2 for x and -1 for y and solve for r. So:

$(-2+4)^2+(-1-8)^2=r^2$

Evaluate:

$(2)^2+(-9)^2=r^2$

Square:

$4+81=r^2$

Add:

$r^2=85$

So, r squared is 85.

We don’t actually have to solve for r itself, since we will have to square it anyways.

So, we have:

$(x+4)^2+(y-8)^2=r^2$

Substituting 85 for r squared, we get:

$(x+4)^2+(y-8)^2=85$

And we have our equation.

8 0

2 years ago

What is the x-value when y is 0?

aleksley [76]

Answer:

Step-by-step explanation:

2 bc 1 is 3 and your going down one so 0 is 2

8 0

2 years ago

Solve l-20l - l7l PLEASE HELPP IM ON A TEST

tiny-mole [99]

Answer:

Step-by-step explanation:

|-20| = 20 (anything with | | is absolute value, which is always positive), |7| = 7, 20 - 7 = 13.

quick tip: when you see something like -|#|, that would be negative, but if you saw |-#|, it would be positive.

hope it helps lol

7 0

3 years ago

Sophia factored 81y^6 as (9y^3)(9y^2) Ahmed factored 81y^6 as (3y^6)(27y) Which of them factored 81y^6 correctly?

ladessa [460]

answer: neither Sophia nor Ahmed answered correctly, you can’t factor the equation with rational numbers

3 0

3 years ago