X^4+2x^2-48=0 what is the solution set
1 answer:
Answer:
x. = sqrt 6 and x = - sqrt 6
Step-by-step explanation:
x^4 + 2x^2-48=0
(x^2 - 6) (x^2 + 8) = 0
x^2 - 6 = 0
x = + sqrt 6 and x = - sqrt 6
x^2 + 8 = 0
x^2 = sqrt -8 (a negative number doesn’t have a real square root)
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