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3 years ago

5. List three safety concerns when using hand ertain safety tools.

Computers and Technology

1 answer:

sveta [45]3 years ago

6 0

Answer:

Inspect regularly. ...

Wear gloves. ...

Carry with care. ...

Don't pocket sharp objects. ...

Be aware of your surroundings. ...

Use the right tools.

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A(n) ____________________ is hardware or software that blocks or allows transmission of information packets based on criteria su

QveST [7]

Answer:

The answer is "Packet Filter(144-145)".

Explanation:

This technique is used in firewalls, which monitors access to the network, track data transmission packets, transfer or stop based on IP protocols and ports.

This approach is often used to test modulation packets.
It also used to control performance and provides security.
This mechanism also used in the IPv6.

6 0

3 years ago

Most of the internal operations in a computer use hexagonal numbering true or false

dolphi86 [110]

Answer:

True

Explanation:

The hexadecimal numbering is the most used numeric system for international operations in a computer, in our daily life we use the decimal system but for the CPU use the byte or octet as a basic unit of memory, we need more than 10 digits, and the hexadecimal system has 16, in addition, the binary system is hard to understand.

4 0

3 years ago

The inability of BAE Automated Systems to create an automated baggage handling system led to a significant delay in the opening

Sergeu [11.5K]

Answer:

True

Explanation:

Airport was truly opened outside the city of Denver, because of the faults in BAE automated system.

6 0

3 years ago

What steps can be used to password-protect a worksheet?

muminat

Answer:

Review

Changes

Protect sheet

Explanation:

I did it

8 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago