Answer:
second_int = "Enter the second integer: "
usernum = int(input("Enter the first integer: "))
x = int(input(second_int))
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum, end= ' ')
usernum = usernum // x
print(usernum)
Explanation:
im good
Answer:
128 GB
Explanation:
Here, we are interested in calculating the total capacity of the disk.
From the question, we can identify the following;
Number of surfaces = 4
Tracks per surface = 131,072
Number of sectors = 2,048
Each Block size = 512 bytes
Mathematically;
Total data capacity of the disk = no of tracks * no of sectors * block size
= 131,072 * 2048 * 512 bytes
= 2^17 * 2^11 * 2^9 bytes = 2^37 bytes
1 GB = 2^30 bytes
So 2^37 = 2^7 * 2^30
= 128 GB
Answer:
- import java.util.Scanner;
- public class Main {
-
- public static void main(String[] args) {
-
- Scanner input = new Scanner(System.in);
- System.out.print("Please enter two characters: ");
- String inputStr = input.nextLine();
-
- if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
- System.out.println("Biology");
- }
- else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
- System.out.println("Computer Science");
- }
- else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
- {
- System.out.println("Information Technology and Systems");
- }
- else{
- System.out.println("Invalid major");
- }
-
- int num = Character.getNumericValue(inputStr.charAt(1));
-
- if(num >= 1 && num <= 4){
- switch (num){
- case 1:
- System.out.println("freshman");
- break;
- case 2:
- System.out.println("sophomore");
- break;
- case 3:
- System.out.println("junior");
- break;
- case 4:
- System.out.println("senior");
- break;
- }
-
- }
- else{
- System.out.println("Invalid year status");
- }
-
- }
-
- }
Explanation:
The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.
The part 2 is to validate the year status to make sure it only fall within the range of 1-4 (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.
Answer:
The time complexity of the code is O(log₇n).
Explanation:
The i is updated by 7*i.On each iteration i is multiplied by 7.So on finding the time complexity of the code given above it will come out to be log base 7.
When we divide the input by 2 the time complexity is log base 2.
So on dividing it by 7 we get the time complexity of log base 7.
