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Ira Lisetskai [31]
3 years ago
10

Write the definition of a method, oddsMatchEvens, whose two parameters are arrays of integers of equal size. The size of each ar

ray is an even number. The method returns true if and only if the even-indexed elements of the first array equal the odd-indexed elements of the second, in sequence. That is if w is the first array and q the second array, w[0] equals q[1], and w[2] equals q[3], and so on.
Computers and Technology
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

public boolean oddsMatchEvens(int[ ] w, int[ ] q) {

   for (int i = 0; i < w.length-1; i+=2) {

        if (w[i] != q[i + 1])

           return false;

        else

           continue;

   }

   return true;

}

Explanation:

Since it was mentioned that both arrays are of equal length, we use the length of the first array minus one as our condition in order check the last item. Then, we have to check first array even with second array odd so we increment by be i+=2 and not the popular i++. The continue statement ensures that as soon as only one case fails, the loop with stop and return true.

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Write a program that asks the user to enter a number of seconds. There are 60 seconds in a minute. If the number of seconds ente
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Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

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long long int second;

printf("enter seconds:");

// read the seconds

scanf("%lld",&second);

// if seconds is in between 60 and 3600

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printf("there are %d minutes in %lld seconds.",min,second);

}

// if seconds is in between 3600 and 86400

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// if seconds is greater than 86400

else if(second>86400)

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int days=second/86400;

printf("there are %d minutes in %lld seconds.",days,second);

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return 0;

}

Explanation:

Read the seconds from user.If the seconds is in between 60 and 3600 then find the minutes by dividing seconds with 60 and print it.If seconds if in between 3600 and 86400 then find the hours by dividing second with 3600 and print it. If the seconds is greater than 86400 then find the days by dividing it with 86400 and print it.

Output:

enter seconds:89

there are 1 minutes in 89 seconds.

enter seconds:890000

there are 10 days in 890000 seconds.

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