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UNO [17]
3 years ago
10

Point B is on line segment AC. Given AB = 2x + 10, BC = x, and AC = 5x,

Mathematics
1 answer:
denpristay [2]3 years ago
4 0

Answer:

x = 5 segment AC = 25

Step-by-step explanation:

if 'A' to 'B' is 2x + 10 and 'B' to 'C' is x, then we need to add those values together to get from 'A' to 'C'

2x + 10 + x = 5x

add the 'x' values

3x + 10 = 5x

then subtract the '3x's from both sides

10 = 2x

finally, divide both sides by two

5 = x

meaning.....

5 • 5 (for the 5x) is equal to 25

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3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared
navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

#SPJ1

8 0
2 years ago
A photograph club has 100 members and 45 are women what fraction of the members represent women
avanturin [10]
It could be 45/100 but I'm sure you can simplify it.
6 0
3 years ago
6,372<br> x 75<br> ________ Equal to what answer?
givi [52]
6,372 x 75 = 477,900
7 0
3 years ago
Read 2 more answers
At what value of x does the graph of the following function F(x) have a
Free_Kalibri [48]

Answer:

B

Step-by-step explanation:

Given

f(x) = \frac{1}{x+2}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

6 0
3 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted longer than the manufacturer's claim that
rosijanka [135]

Answer:

C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.

Step-by-step explanation:

Data given and notation  

\bar X=14.5 represent the sample mean

s=1.2 represent the sample standard deviation

n=40 sample size  

\mu_o =14 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 14, the system of hypothesis would be:  

Null hypothesis:\mu \leq 14  

Alternative hypothesis:\mu > 14  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{14.5-14}{\frac{1.2}{\sqrt{40}}}=2.635    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.635)=0.006  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis

The best option would be:

C) t = 2.635; p = 0.006; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last longer than 14 hours.

4 0
3 years ago
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