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3 years ago

Answer: find the value of 4v-3 given that -5v-2=3. Simplify your answer as much a possible.

1 answer:

3 0

First you find the value of v, using the equation -5v - 2 = 3. You can't do anything with 4v - 3 yet because it doesn't have a value, an equal sign.

-5v - 2 = 3

Simplify by isolating the variable v in one side of the equation and the value in the other

Add 2 to both sides to shift -2 to the other side

-5v - 2 + 2 = 3 + 2

-5v = 5

Divide both aides by -5

-5v ÷ (- 5 ) = 5 ÷ (-5)

v = -1

Now you got the value of v

Plug v = -1 into 4v - 3

4×(-1) - 3

-4 - 3 = 7

4v - 3 = -7

Hope it helps :)

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What is the least common multiple of two numbers that have no common factors greater than 1

Maksim231197 [3]

7 and 6 and the LCM would be 42

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2 years ago

1. (Sec. 6.1) In a random sample of 80 components of a certain type, 12 are found to be defective. (a) Give a point estimate for

denis-greek [22]

Answer:

(a) 0.85

(b) 0.7225

Step-by-step explanation:

(a) The point estimate for the proportion of all such components that are not defective is given by the number of non-defective units in the sample divided by the sample size:

$p=\frac{80-12}{80}\\p=0.85$

The proportion is 0.85.

(b) Assuming that the sample is large enough to accurately provide a point estimate for the whole population, this can be treated as a binomial model with probability of success (non-defective part) p = 0.85. Since both components must be non-defective for the system to work, the probability of two successes in two trials is:

$P(x=2) = 0.85^2\\P(x=2) = 0.7225$

An estimate of 0.7225 for the proportion of all such systems that will function properly.

4 0

2 years ago

Use the given information below to determine the value of x.

Nadusha1986 [10]

C. Bc it is the only one that makes sense

4 0

2 years ago

I literally dont understand this at all please help

wariber [46]

Nobody is going to answer all that for 10 points lol

5 0

3 years ago

SOS PLZ IDK THIS VERY WELL NEED HELP

zaharov [31]

Answer:

1. a. 25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. b. Mark’s average < Jay’s average

Step-by-step explanation:

1. What is Mark’s slugging average?

The slugging average gives more weight to the multi-base hits (compared to single-base hits) in opposition with the batting average.

So, a single hit is worth 1 point, a double is worth 2 points, a triple 3 points and a homerun is worth 4 points. It's a weighted average calculation.

Mark had 25 singles, 10 doubles, 3 triples and 10 homeruns during 140 presences 140 at bat.

25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. How does Mark's average compares to Jay's?

Let's first calculate Jay's slugging average then we'll be able to decide.

Jay had 10 singles, 6 doubles, 5 triples and 14 homeruns in 90 presences.

10 (1) + 6 (2) + 5 (3) + 14 (4) = 10+12+15+56 = 93 / 90 = 1.033

We can definitely say that Mark's slugging average (0.671) calculated above is lower than Jay's average (1.033). So,

b. Mark’s average < Jay’s average

8 0

3 years ago