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tamaranim1 [39]
2 years ago
14

1. (Sec. 6.1) In a random sample of 80 components of a certain type, 12 are found to be defective. (a) Give a point estimate for

the proportion of all such components that are not defective. (b) A system is to be constructed by randomly selecting two of these components and connecting them in a series. The series will function only if neither component is defective. Give an estimate for the proportion of all such systems that will function properly.
Mathematics
1 answer:
denis-greek [22]2 years ago
4 0

Answer:

(a) 0.85

(b) 0.7225

Step-by-step explanation:

(a) The point estimate for the proportion of all such components that are not defective is given by the number of non-defective units in the sample divided by the sample size:

p=\frac{80-12}{80}\\p=0.85

The proportion is 0.85.

(b) Assuming that the sample is large enough to accurately provide a point estimate for the whole population, this can be treated as a binomial model with probability of success (non-defective part) p = 0.85. Since both components must be non-defective for the system to work, the probability of two successes in two trials is:

P(x=2) = 0.85^2\\P(x=2) = 0.7225

An estimate of 0.7225 for the proportion of all such systems that will function properly.

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Dmitry_Shevchenko [17]

Mel should use the least  common multiple to solve the problem

<u>Solution:</u>

Given, Mel has to put the greatest number of bolts and nuts in each box so each box has the same number of bolts and the same number of nuts.  

We have to find that should Mel use the greatest common factor or the least common multiple to solve the problem?

He should use least common multiple.

Let us see an example, suppose 12 bolts and nuts are to be fit in 6 boxes.

Then, if we took H.C.F of 12 and 6, it is 6, which means 6 bolts and nuts in each box, but, after filling 2 boxes with 6 bolts and nuts, there will be nothing left, which is wrong as remaining boxes are empty.

So the remaining method to choose is L.C.M.

Hence, he should use L.C.M method.

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3 years ago
Sven has $1 and a dime in his pile. Dayna has 11 dimes in her pile. If Sven gives Dayna $1 and Dayna gives Sven 10 dimes, will t
viva [34]

Answer:

Yes

Step-by-step explanation:

Because a dollar and a dime and 11 dimes are equal in value ($1.10)

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8 0
2 years ago
A sweet factory produces 5 different chocolate bars. the different flavors are always produced in the same proportions, for ever
IRISSAK [1]

a. There are 933 chocolate bars

b. There are 1200 chocolate bars

c. There are 1580 chocolate bars

<h3>How to calculate the number of chocolate bars</h3>

Since there are 5 different flavors,

let

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  • y = coconut flavored bars,
  • z = coffee flavored bars,
  • a = strawberry flavored bars and
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Since the different flavors are always produced in the same proportions, for every 4 coconut flavored bars 5 honeycomb 6 orange 1 coffee and 4 strawberry

So, the ratio of their proportions are x:y:z:a:b = 6:4:2:1:5

So, the total ratio is T = 6 + 4 + 1 + 4 + 5 = 20

<h3>a. What is the total number of chocolate bars if there are 280 orange flavored bars?</h3>

Since we have 6 orange flavored bars, the ratio of orange flavored bars to total is 6/20

So, the amount of orange flavored bars is x = 6/20 × X

Making X subject of the formula, we have

X = 20x/6

So, if there are 280 orange bars, there will be

X = 20x/6

X = 20 × 280/6

X = 5600/6

X = 933.33

X ≅ 933 chocolate bars

So, there are 933 chocolate bars

<h3>b. What is the total number of chocolate bars if there are 960 coconut flavored bars?</h3>

Since we have 4 coconut flavored bars, the ratio of coconut flavored bars to total is 4/20

So, the amount of coconut flavored bars is y = 4/20 × X

Making X subject of the formula, we have

X = 20y/4

So, if there are 960 coconut flavored bars, there will be

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X = 20 × 960/4

X = 5 × 240

X = 1200 chocolate bars

So, there are 1200 chocolate bars

<h3>c. What is the total number of chocolate bars if there are 79 coffee flavored bars?</h3>

Since we have 1 coffee flavored bars, the ratio of coffee flavored bars to total is 1/20

So, the amount of coconut flavored bars is z = 1/20 × X

Making X subject of the formula, we have

X = 20z

So, if there are 79 coffee flavored bars, there will be

X = 20z

X = 20 × 79

X = 1580 chocolate bars

So, there are 1580 chocolate bars

Learn more about ratio here:

brainly.com/question/1127546

#SPJ1

7 0
1 year ago
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Ratling [72]

Answer:

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snow_lady [41]
SImple,

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