Answer:
option b)
tan²θ + 1 = sec²θ
Step-by-step explanation:
The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.
hypotenuse² = height² + base²
Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.
<h3>1)</h3>
sin²θ + 1 = cos²θ incorrect
<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>
by dividing first identity by cos²θ
sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ
<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>
1 - cot²θ = cosec²θ incorrect
by dividing first identity by sin²θ
sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ
<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>
1 - cos²θ = tan²θ
not such pythagorus identity exists
Yes the lines are parallel
(d(5) -d(3))/(5 -3) = (350 -126)/2 = 112 . . . . . meters/second
112 m/s; it represents the average speed of the object between 3 seconds and 5 seconds
The answer is A each country's economy!
Answer:
The function a (t) is a vector function composed of the component functions 
and 
. How 
are infinitely derivable functions in R, so they are regular functions in R.
Now, for
, you have to 
. How the functions are periodic functions with period 
the vector function 
will take the same point 
at 
then the vector function is auto-intercepted
Step-by-step explanation:
